current of 0.500 A flows through a cell containing Cd(II) for 10.0 minutes. Calculate the maximum moles of Cd removed from the solution? Assume that the current remains constant.

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A: Answer - Reference electrodes - A reference electrode is an electrode which has a stable and…

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A:

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A: Given:E0red=+1.34 VE0c=1.20 V

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A: Time = 171 minutes  Current = 15.0 amperes  Chromium deposited during the process of electrolysis =…

Q: A current of 0.500 A flows through a cell containing Cd(II) for 10.0 minutes. Calculate the maximum…

A: Current Strength = 0.500 A time = 10 min         = 10 × 60 sec                               (As, 1…

Q: Fischl, a scientist from Mondstadt specializing in electrochemistry, performed an electrolytic cell…

A: Given Amount of metal deposited = 15.73 g Current = 1.5 A Time = 5 hours n = 2

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Q: A certain half-reaction has a standard reduction potential E=-1.33 V. An engineer proposes using…

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A: Given:  Current = 0.974 A  Time = 67.4 min = 67.4 x 60 = 4044 sec

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Q: What mass of chromium could be deposited by electrolysis of an aqueous solution of Cr2(SO4)3 for 181…

A: Given data: The time taken for the electrolysis of Cr2(SO4)3 is t=180 min. The current produced is…

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Q: A certain half-reaction has a standard reduction potential E=+0.41 V. An engineer proposes using…

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A: E˚cathode  is given as 0.01 V. E˚cell  is 1.00 V. Thus E˚anode can be calculated as follows:

Q: What mass of chromium could be deposited by electrolysis of an aqueous solution of Cr2(SO4)3 for 160…

A: Time = 160 minutes  Current = 12.0 ampere  Mass of chromium deposited during electrolysis = ?

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A: ·  change(Q)=current(i)×time(t)· 1F change passed to cu2+ solution to deposite…

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Q: A current of 0.500 A flows through a cell containing Cd(II) for 10.0 minutes. Calculate the maximum…

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Q: A certain half-reaction has a standard reduction potential =E0red−0.34V . An engineer proposes…

A:

Q: A current of 0.500 A flows through a cell containing Cd(II) for 10.0 minutes. Calculate the maximum…

A: Given:  Current(I) = 0.500 A  Time(t) = 10 min. = 600 sec

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A: "To get remaining sub-parts solved please repost the complete question and mention the sub-parts to…

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