Question

Asked Sep 17, 2019

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Chapin Manufacturing Company operates 24 hours a day, five days a week. The workers rotate shifts each week. Management is interested in whether there is a difference in the number of units produced when the employees work on various shifts. A sample of five workers is selected and their output recorded on each shift. At the 0.01 significance level, can we conclude there is a difference in the mean production rate by shift or by employee?

Units Produced | |||

Employee | Day | Afternoon | Night |

Skaff | 37 | 27 | 34 |

Lum | 35 | 26 | 38 |

Clark | 24 | 23 | 22 |

Treece | 22 | 20 | 25 |

Morgan | 30 | 26 | 37 |

- What is your decision regarding
*H*_{0}?**(Round your answers to 2 decimal places.)**

from tretmant: reject H0 if F>

from block:Reject H0 if F>

2.What is your conclusion?

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Question 6 of 7 Total**6**of 7

PrevStep 1

In order to test whether there is a difference in the mean production rate by shift or by employee, two-factor ANOVA is appropriate.

Here, the column represents treatments and row represents blocks.

**Two-factor ANOVA:**

Step-by-step procedure to perform two-factor ANOVA using excel:

- Enter the data in sheet1
- Select
**Data > Data Analysis**. - Choose
**Anova: Two-factor without replication**. - In
**Input Range**, select**$B$1:$D$6.** - In
**Alpha**, enter**01**. - Click

The output obtained is as follows.

Step 2

**Decision regarding H0:**

*Null hypothesis:*

There is no difference in the mean production rate by shift.

There is no difference in the mean production rate by employee*.*

*Alternative hypothesis:*

There is difference in the mean production rate by shift.

There is difference in the mean production rate by employee.

*Critical value for treatment:*

The critical value for treatment is obtained as **8.6491** using the excel formula, “=F.INV.RT(0.01,2,8)&rdqu...

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