The cadmium and lead ions in a 50.00 mL sample required 40.09 mL of a 0.005000 M EDTA for titration. A 75.00 mL portion of the same sample was made basic and treated with excess KCN masking the cadmium as Cd(CN)42-. This solution required 21.42 mL of the EDTA for titration. Calculate the concentration of Cd2+ and Pb2+ in the sample ppm and in M.

The cadmium and lead ions in a 50.00 mL sample required 40.09 mL of a 0.005000 M EDTA for titration. A 75.00 mL portion of the same sample was made basic and treated with excess KCN masking the cadmium as Cd(CN)42-. This solution required 21.42 mL of the EDTA for titration. Calculate the concentration of Cd2+ and Pb2+ in the sample ppm and in M.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.33QAP

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