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CODE int Num1 = 6; int Num2 = 5; float Result; void setup(){ Serial.begin(9600); Result = (float) Num1 / Num2; Serial.println("Division of Num1 and Num2 is "); Serial.printin("Num1 and Num2 is "); Serial.printIn(Result); Serial.printin(Num1);

CODE int Num1 = 6; int Num2 = 5; float Result; void setup(){ Serial.begin(9600); Result = (float) Num1 / Num2; Serial.println("Division of Num1 and Num2 is "); Serial.printin("Num1 and Num2 is "); Serial.printIn(Result); Serial.printin(Num1);

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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CODE int Num1 = 6; int Num2 = 5; float Result; void setup(){ Serial.begin(9600); Result = (float) Num1 / Num2; Serial.printIn("Division of Num1 and Num2 is "); Serial.printin("Num1 and Num2 is "); Serial.printin(Result); Serial.printin(Num1);
Transcribed Image Text:CODE int Num1 = 6; int Num2 = 5; float Result; void setup(){ Serial.begin(9600); Result = (float) Num1 / Num2; Serial.printIn("Division of Num1 and Num2 is "); Serial.printin("Num1 and Num2 is "); Serial.printin(Result); Serial.printin(Num1);
void loop() { } OUTPUT of and is and is
Transcribed Image Text:void loop() { } OUTPUT of and is and is
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