Compare and contrast types of inhibition based on information given. Part 1 Complete Table by replacing double question marks (??) with one of the types inhibition indicated below and single question marks with Increase, Decrease, c No change in velocity compared with control Restrict inhibition to the following types • Change • Competitive • Non-competitive Uncompetitive None Trial Km Vmax (S) [Cofactor] V (dp/dt) Inhibition Control 1 1 1 0.5 ?? 1 Decrease Increase 1 Increase 3 ?? 1 1 ?? 1 [E;) represents total enzyme concentration Part 2 Explain why the velocity in trial 1 must be 0.5 based on Michaelis-Menten Enzyme kinetics Identify the trials that could be explained by allosteric inhibition. Explain. Identify the trials that could be explained by allosteric activation. Explain

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Compare and contrast types of inhibition based on information given.
Part 1
Complete Table by replacing double question marks (??) with one of the types
inhibition indicated below and single question marks with Increase, Decrease, c
No change in velocity compared with control
Restrict inhibition to the following types
• Change
• Competitive
• Non-competitive
Uncompetitive
None
Trial
Km
Vmax
(S)
[Cofactor]
V (dp/dt)
Inhibition
Control
1
1
1
0.5
??
1
Decrease
Increase
1
Increase
3
??
1
1
??
1
[E;) represents total enzyme concentration
Part 2
Explain why the velocity in trial 1 must be 0.5 based on Michaelis-Menten
Enzyme kinetics
Identify the trials that could be explained by allosteric inhibition. Explain.
Identify the trials that could be explained by allosteric activation. Explain
Transcribed Image Text:Compare and contrast types of inhibition based on information given. Part 1 Complete Table by replacing double question marks (??) with one of the types inhibition indicated below and single question marks with Increase, Decrease, c No change in velocity compared with control Restrict inhibition to the following types • Change • Competitive • Non-competitive Uncompetitive None Trial Km Vmax (S) [Cofactor] V (dp/dt) Inhibition Control 1 1 1 0.5 ?? 1 Decrease Increase 1 Increase 3 ?? 1 1 ?? 1 [E;) represents total enzyme concentration Part 2 Explain why the velocity in trial 1 must be 0.5 based on Michaelis-Menten Enzyme kinetics Identify the trials that could be explained by allosteric inhibition. Explain. Identify the trials that could be explained by allosteric activation. Explain
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