Consider a computer system that uses virtual memory with paging (no TLB). Suppose main access time is 50 ns and no page faults. What is the effective memory access time (express in ns)
Q: the AMAT (in number of clock pulses)?
A: The AMAT (in number of clock pulses)
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A: Introduction Consider a system with 20 requests and out of 20 , 4 requests are already in cache…
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A: The Answer is in step2
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A: The Answer is
Q: Consider a computer system that uses virtual memory with paging (no TLB). Suppose main access time…
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A: The answer is
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A:
Q: How many bits are in a physical address?
A: There are 4 pages frames of size 64 each, or 22 x 26=28. So each physical address has 8 bits.
Q: Suppose we have a computer system with 44-bit logical addresses, page size of 64KiB, and 4 bytes per…
A: The answer is explained in detailed below:
Q: Suppose the page table for the process currently executing on the processor looks like the…
A:
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A: Given Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses.(a) What is…
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Q: Consider a system with 39-bit virtual addresses, 44-bit physical addresses, 4096 byte pages, and
A: The answer is
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A: As we know Physical address = page size*frame number + offset
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A: Below is the answer to above question. I hope this will be helpful for you..
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A: Introduction :Given A system , on average, an instruction executes in 1 nano second.page fault…
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- Consider a system with N bytes of physical RAM, and M bytes of virtual address and frames are K bytes in size. The number of pages is equal:Consider a memory-management system based on paging. The total size of the physical address space 64 MB, Pages of size 4 KB, the Logical address space of 4GB. total number of pages are 16384, total number of frames are 16384 and the number of entries in a page table are 1048576.Now Calculate: a)Size of Page Table b) No of bits in Physical Address c) No of Bits in Logical AddressSuppose a computer system uses 16 but addresses for both virtual and physical address. In addition, assume each page (and frame) has a size of 256 bytes. -How many bits are used for page number? -How many bits for offset? -what is the max number of pages a process can have?
- Suppose a two layer memory hierarchy has a 4 clock pulse hit time, a 35 clock pulse miss penalty, and the miss ratio is 20%. What is the AMAT (in number of clock pulses)?Consider an operating system using memory mapping on a page basis and using a single level page table. Assume that the necessary page table is always in memory. The system takes 200 ns to make a memory reference, how long does a paged memory reference take? Group of answer choices 400 ns (nanoseconds) 809.2 ms (microseconds) 200 ns (nanoseconds) 1638.4 ms (microseconds)Consider a logical address space of 32 pages of 1024 words each, mapped onto a physical memory of 8 frames. How many bits are there in logical address and how many bits are there in physical address?
- A system with simple paged memory management has addresses of B bits and pages of size P KiB. If all memory is pageable, what is the maximum number of items contained in a process's page table? What if K KiB are reserved for the kernel and are not pageable? Also suppose that the page table is organized in 2 levels, so that the page directory (first level) is addressed by D bits. How many bits will be used to address the second level? How many entries will there be, at most, among all the tables of the pages (first and second level) of a process?Suppose we have a computer system with a 44-bit virtual address, page size of 64 KB. How many pages are in the virtual address space?Given a virtual memory of size 4 GiB, physical memory of size 1 GiB, and page size equal to 256 KiB. How many bits are used to specify a virtual page number?
- Consider a computer system with a 64-bit logical address and 32-KB page size. Thesystem supports up to 4096 MB of physical memory. How many entries are there ineach of the following?a. A conventional single-level page table?b. An inverted page table?Consider a computer which uses virtual addressing with 32 bit addresses and a two level page table. The virtual addresses are split into a 9 bit top level page table field, an 11 bit second level page table field and an offset. How large are the pages and, how many are there in the address space?Consider a memory system with a cache access time of 100ns and a memory access timeof 1200ns. If the effective access time is 10% greater than the cache access time, what is thehit ratio H?