Consider the following recursive algorithm. 1]) ALGORITHM Riddle(A[0..n â^' 7/Input: An array A[0..n â^' 1] of real numbers if n == 1 return A[0]; else temp <- Riddle(A[0..n â^' 2]) if temp â%o A[n â^' 1] return temp else return A[n â^' 1]
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- 1. Design an algorithm to find the weighted sum of four test scores (https://en.wikipedia.org/wiki/Weight_function). Assume that the weights have been accurately calculated in advance such that their sum equals one. Your algorithm must-read in the four test scores and four corresponding weights in the following order: score1 weight1 score2 weight2 score3 weight3 score4 weight4 Write your algorithm such that it can be run with any set of data values. However, you can test your algorithm on the following sample data to verify that the result is 70: 90 0.10 80 0.20 70 0.30 60 0.40 2. Write an algorithm that prompts the user for the radius, in inches, and price of a pizza, and then reads in those values. Finally, have the algorithm compute and output the pizza’s cost per square inch. 3. Sports exercise advisor algorithm. In this algorithm you will start out with a temperature value in Celsius, so you do not need to ask the user for it. First, convert the temperature to Fahrenheit.…Where i need help has multiple parenthesis beside them thank you. def readMatrix(inputfilename): ''' Returns a two-dimentional array created from the data in the given file. Pre: 'inputfilename' is the name of a text file whose first row contains the number of vertices in a graph and whose subsequent rows contain the rows of the adjacency matrix of the graph. ''' # Open the file f = open(inputfilename, 'r') # Read the number of vertices from the first line of the file n = int(f.readline().strip()) # Read the rest of the file stripping off the newline characters and splitting it into # a list of intger values rest = f.read().strip().split() # Create the adjacency matrix adjMat = [] (I need help creating the adjacency matrix)()() ... # Return the matrix return adjMat testFile = input("Enter the name of the input file")graphMatrix = readMatrix(testFile)graphMatrix def Prim(m): ''' Runs Prim's…please code in python The bisection code below finds the square root of a number. Try inputting 16 into the code to confirm it works. Next, try inputting 0.25 into the bisection search algorithm below and confirm that it doesn't work. Then correct the algorithm so that it works for all positive numbers, including decimals such as 0.25. # Q4-3 Grading Tag: ## Please fix the code in this cell (that is don't make a new cell)## Bisection Search to Find a Square Root x = float(input("enter a number:")) epsilon = 0.00001num_guesses = 0low = 0.0high = xans = (high + low)/2.0 while high - low >= 2 * epsilon: print("low =",low,"high =", high) num_guesses += 1 if ans ** 2 < x: low = ans else: high = ans ans = (high + low)/2.0 # Do not modify these output statements as the autograder looks for these!print('Number of guesses =', num_guesses)print(ans, 'is close to square root of', x)
- 4.15 LAB: Password modifier Many user-created passwords are simple and easy to guess. Write a program that takes a simple password and makes it stronger by replacing characters using the key below, and by appending "q*s" to the end of the input string. i becomes ! a becomes @ m becomes M B becomes 8 o becomes . Ex: If the input is: mypassword the output is: Myp@ssw.rdq*s Hint: Python strings are immutable, but support string concatenation. Store and build the stronger password in the given password variable.Q/Complete the following code in Python language (biometrics) for voice recognition and apply the code, mentioning the approved source if it exists import osimport numpy as npfrom pyAudioAnalysis import audioBasicIO, audioFeatureExtraction, audioTrainTestfrom pydub import AudioSegment# Function to capture and save voice samplesdef capture_voice_samples(num_samples, speaker_name):os.makedirs("speakers", exist_ok=True)os.makedirs(f"speakers/{speaker_name}", exist_ok=True)for i in range(num_samples):input(f"Press Enter and start speaking for sample {i + 1}...")# Recording audio using pyAudioAnalysisaudio = audioBasicIO.record_audio(4, 44100)filepath = f"speakers/{speaker_name}/sample_{i + 1}.wav"audioBasicIO.write_audio_file(filepath, audio, 44100)print(f"Sample {i + 1} saved for {speaker_name}")# Function to extract features from voice samplesdef extract_features():speakers = [d for d in os.listdir("speakers") if os.path.isdir(os.path.join("speakers", d))]all_features = []all_labels =…PLEASE CODE IN PYTHON Crypto Columns The columnar encryption scheme scrambles the letters in a message (or plaintext) using a keyword as illustrated in the following example: Suppose BATBOY is the keyword and our message is MEET ME BY THE OLD OAK TREE. Since the keyword has 6 letters, we write the message (ignoring spacing and punctuation) in a grid with 6 columns, padding with random extra letters as needed: MEETME BYTHEO LDOAKT REENTH Here, we've padded the message with NTH. Now the message is printed out by columns, but the columns are printed in the order determined by the letters in the keyword. Since A is the letter of the keyword that comes first in the alphabet, column 2 is printed first. The next letter, B, occurs twice. In the case of a tie like this we print the columns leftmost first, so we print column 1, then column 4. This continues, printing the remaining columns in order 5, 3 and finally 6. So, the order the columns of the grid are printed would be 2, 1, 4, 5, 3, 6, in…
- Time remaining: 01:59:44 Computer Science //Change the code so that it is a "DataStore with Vectors & 3-files" #include <iostream>using namespace std;int main(){ int n; cout << "How Many: "; cin >> n; double *pScore = new double[n]; for (int x = 0; x < n; x++) { cout << "Enter Score: "; cin >> pScore[x]; } for (int x = 0; x < n; x++) cout << pScore[x] << " " << &pScore[x] << endl; return 0; }3.37.1: String access operations. Given string inputText, output "Match found" if the first character of inputText is 'w'. Otherwise, output "Match not found". End with a newline. Ex: If the input is: warmth then the output is: Match found Note: Assume the length of string inputText is greater than or equal to 1. 1 2 3 4 5 6 7 8 9 10 11 12 13 import java.util.Scanner; public class CharMatch { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); StringinputText; inputText=scnr.nextLine(); /* Your code goes here */ } } import java.util.Scanner; public class CharMatch { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputText; inputText = scnr.nextLine(); /* Your code goes here */ }}python: def dna_slice(strand, first_nucleotides, last_nucleotides): """ Question 3 - Regex You are working with a long strand of DNA. Your task is to find and return the length of the first substrand that begins with the two-letter sequence specified in first_nucleotides and ends with the sequence specified in last_nucleotides. THIS MUST BE DONE IN ONE LINE. Args: strand (str) first_nucleotides (str) last_nucleotides (str) Returns: int strand_1 = 'TATGGGTCGAGCATGT' >>> dna_slice(strand_1, 'AT', 'CG') 8 >>> dna_slice(strand_1, 'GT', 'TG') 10 """ strand_1 = 'TATGGGTCGAGCATGT' pprint(dna_slice(strand_1, 'AT', 'CG')) pprint(dna_slice(strand_1, 'GT', 'TG'))
- 5.13 LAB: Password modifier Many user-created passwords are simple and easy to guess. Write a program that takes a simple password and makes it stronger by replacing characters using the key below, and by appending "!" to the end of the input string. i becomes 1 a becomes @ m becomes M B becomes 8 s becomes $ Ex: If the input is: mypassword the output is: Myp@$$word! Hint: Python strings are immutable, but support string concatenation. Store and build the stronger password in the given password variable. my code: please help me word = input() password = '' # Modify characters i, a, m, B, and o in passwordfor character in word: if character == 'i': # IF character equals 'i' change to '!' password += '!' elif character == 'a': # ELSE IF character equals 'a' change to '@' password += '@' elif character == 'm': # ELSE IF character equals 'm' change to 'M' password += 'M' elif character == 'B': # ELSE IF character equals 'B'…JAVA INTELLIJ Design an experiment to compare the Selection, Insert, and Bubble Sort Algorithms. Comments in code please so I understand! Thanks :) Come up with a collection of questions that pertain to comparing algorithms. (i.e. How do they compare with small groups of data, large groups of data, semi-sorted data , data in a small range, data in a large range, etc). After that, design, code, and run the experiment. **PLEASE WRITE SEPERATE PARAGRAPH WITH ANSWERED QUESTIONS** Lastly, a writeup explaining what you did, your results (what the experiment yielded), and your conslusions (how you interpret them). The following questions need to be addressed: – What questions were you looking at? – How you decided to look at them? – What did you do? – What were the results? – What are your conclusions?Please i need help! Historgram( on Jupyter Notebook in Python) 1. A dice is thrown multiple times. Show the occurences of all numbers 1-6 using bar charts (histograms) for four (4) values of size(n): 10505001000You must use subplots(2,2), with two (2) rows and two (2) colummns. Also, there must be title and labels (x-axis and y-axis) for all four (4) histograms. Write a code that will give you an output below? Text0, 0.5, 'Number of Samples'