Consider the following structures for NO3. Which one contributes most to the overall structure of the compound? A B с OA B -N=O: Ос :O: They all contribute equally. -O: [T] :O: O=N-O: :0: O None of the structures contribute
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![Consider the following structures for NO3. Which one contributes most to the overall structure of the compound?
A
B
с
OA
B
-N=O:
Ос
:O:
They all contribute equally.
-O:
[T]
:O:
O=N-O:
:0:
O None of the structures contribute](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf6c3174-f071-4892-a981-9c51afb6153d%2F1456f7a1-e0a9-414c-ae3e-9abe2e9e5026%2F3guip0i_processed.png&w=3840&q=75)
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 1 images
