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Consider the problem below: (Equation 1) H2(g) + 1/2 O2(g) ---> H2O(l) ΔH = -285.8 kJ/mol (Equation 2) C(s) + O2(g) ---> CO2(g) ΔH = -393.5 kJ/mol (Equation 3) 2 C(s) + H2(g) ---> C2H2(g) ΔH = 226.7 kJ/mol (Equation 4) 2 C2H2(g) + 5 O2(g) ---> 4 CO2(g) + 2 H2O(l) ΔH = ??????? The ΔH for equation 4 is:______(express in kJ) Screen Reader Version Consider the problem below: (Equation 1) H2(g) + 1/2 O2(g) arrow H2O(l) ΔH = minus 285.8 kJ/mol (Equation 2) C(s) + O2(g) arrow CO2(g) ΔH = minus 393.5 kJ/mol (Equation 3) 2 C(s) + H2(g) arrow C2H2(g) ΔH = 226.7 kJ/mol (Equation 4) 2 C2H2(g) + 5 O2(g) arrow 4 CO2(g) + 2 H2O(l) ΔH = ??????? The ΔH for equation 4 is:______(express in kJ)

Consider the problem below: (Equation 1) H2(g) + 1/2 O2(g) ---> H2O(l) ΔH = -285.8 kJ/mol (Equation 2) C(s) + O2(g) ---> CO2(g) ΔH = -393.5 kJ/mol (Equation 3) 2 C(s) + H2(g) ---> C2H2(g) ΔH = 226.7 kJ/mol (Equation 4) 2 C2H2(g) + 5 O2(g) ---> 4 CO2(g) + 2 H2O(l) ΔH = ??????? The ΔH for equation 4 is:______(express in kJ) Screen Reader Version Consider the problem below: (Equation 1) H2(g) + 1/2 O2(g) arrow H2O(l) ΔH = minus 285.8 kJ/mol (Equation 2) C(s) + O2(g) arrow CO2(g) ΔH = minus 393.5 kJ/mol (Equation 3) 2 C(s) + H2(g) arrow C2H2(g) ΔH = 226.7 kJ/mol (Equation 4) 2 C2H2(g) + 5 O2(g) arrow 4 CO2(g) + 2 H2O(l) ΔH = ??????? The ΔH for equation 4 is:______(express in kJ)

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.44QE
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Consider the problem below:

(Equation 1) H2(g) + 1/2 O2(g) ---> H2O(l) ΔH = -285.8 kJ/mol

(Equation 2) C(s) + O2(g) ---> CO2(g) ΔH = -393.5 kJ/mol

(Equation 3) 2 C(s) + H2(g) ---> C2H2(g) ΔH = 226.7 kJ/mol

(Equation 4) 2 C2H2(g) + 5 O2(g) ---> 4 CO2(g) + 2 H2O(l) ΔH = ???????

The ΔH for equation 4 is:______(express in kJ)

Screen Reader Version

Consider the problem below:

(Equation 1) H2(g) + 1/2 O2(g) arrow H2O(l) ΔH = minus 285.8 kJ/mol

(Equation 2) C(s) + O2(g) arrow CO2(g) ΔH = minus 393.5 kJ/mol

(Equation 3) 2 C(s) + H2(g) arrow C2H2(g) ΔH = 226.7 kJ/mol

(Equation 4) 2 C2H2(g) + 5 O2(g) arrow 4 CO2(g) + 2 H2O(l) ΔH = ???????

The ΔH for equation 4 is:______(express in kJ)

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