def large_position(matrix: list[list[int]], row: int, col: int) -> int: a = row b = col max = 0 temp = 0 rows = len(matrix) column = len(matrix[a]) while a < rows and matrix[a][col] == 1: temp = 0 while b < column and matrix[a][b] == 1:

Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7    #include <iostream>using namespace std; int main() {   const int NUM_VALS = 4;   int courseGrades[NUM_VALS];   int i;    for (i = 0; i < NUM_VALS; ++i) {      cin >> courseGrades[i];   }    /* Your solution goes here  */    return 0;}

Which of the following statements regarding linked lists and arrays is correct? Group of answer choices: a. A dynamically resizable array makes insertions at the beginning of an array very efficient.   b. Using a doubly linked list is more efficient than an array when accessing the ith element of a structure.   c. A dynamically resizable array is another name for a linked list.   d. Any type of list tends to be better than an array when there are a set number of maximum items known beforehand.   e. If many deletions at any place in the structure were common, a linked list implementation would likely be preferable to an array

This is a pyhton , Coding the screenshot better explains. It  talks about list

PART A. We will start by finding the largest value.  Initially, we assume that the first element in the list is the largest element and create a variable maxValue that is  initialized to the first element in the array. We then compare the element that maxValue is storing with every  element in the list. Whenever we find an element in the array larger than the element that maxValue is storing,  we update maxValue so that it stores the value of the newer larger element. Algorithm ArrayLargestElement  Declare and initialize maxValue to the first element in the array.  Use a FOR loop to traverse the array.  // You already checked the first element, so you should start the loop at the second element.    If the element at this index is larger than maxValue    Update maxValue  Output maxValue.   Write a program MyArray_ABC that declares an array containing the following elements: 45, 38, 27, 46, 81, 72,  56, 61, 20, 48, 76, 91, 57, 35, and 78, and outputs the largest value.    Additionally,…

For example, suppose the word “robot” is found in lines 7, 18, 94, and 138. The dictionary would contain an element in which the key was the string “robot”, and the value was a list containing the numbers 7, 18, 94, and 138. Once the dictionary is built, you should prompt the user for a word. If the word is found in the dictionary, then print out all the lines on which they are found in ascending order. The code for the print out is provided in the stub code. A stub code is provided for you. If you do not see it, click the "Load default template" button. # The get_word_dict function returns a dictionary containing# the words from line_list as keys, and their line numbers# as values.def get_word_dict(line_list):# Create a line counter.count = 0  # Create a dictionary to hold the words.word_dict = {} # Step through the list of lines.#######Add you code below#############        ####################################### Return the dictionary.return word_dict #####DO NOT CHANGE ANYTHING…