Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Design and implement a Java program/application that
1. Uses at least one of the following collections:
a. Stack
b. Queue
c. List
d. Tree
2. Uses at least one of the following searching methods:
a. Linear search
b. Binary search
3. Uses at least one of the following sorting methods:
a. Bubble sort
b. Insertion sort
c. Selection sort
d. Quick sort
e. Merge sort 

I'm using an insertion sort for this project. I would like help implementing a list collection type and binary search method.

//Project with Insertion sort

import java.util.Random;
public class main{
    static void insertionSort(int arr[]){
        int n = arr.length;
        for (int i = 1; i < n; ++i){
            int key = arr[i];
            int j = i - 1;
            while (j >= 0 && arr[j] > key){
                arr[j + 1] = arr[j];
                j = j - 1;
            }
            arr[j + 1] = key;
        }
    }
 public static void main(String[] args){
      int max = 100;
      int min = 1;
      int arr[]=new int[10];
      Random randomNum = new Random();
      for(int i=0;i<arr.length;i++){
        arr[i] = min + randomNum.nextInt(max);
      }
      System.out.println("Array of random number is: ");
      for(int i=0;i<arr.length;i++){
        System.out.print(arr[i]+ " ");
      }
      insertionSort(arr);
      System.out.println("\nSorted array is: ");
      for(int i=0;i<arr.length;i++){
        System.out.print(arr[i]+ " ");
      }
    }
}

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Follow-up Question

I'd like to know the algorithmic complexity (Big O) of the project below:

import java.util.Random;
import java.util.*;
public class main{
    static void insertionSort(int arr[]){
        int n = arr.length;
        for (int i = 1; i < n; ++i){
            int key = arr[i];
            int j = i - 1;
            while (j >= 0 && arr[j] > key){
                arr[j + 1] = arr[j];
                j = j - 1;
            }
            arr[j + 1] = key;
        }
    }
public static void main(String[] args){
    int max = 100;
    int min = 1;
    int arr[]=new int[10];
    int n;
    @SuppressWarnings("resource")
    Scanner sc=new Scanner(System.in);
    Random randomNum = new Random();
    for(int i=0;i<arr.length;i++){
    arr[i] = min + randomNum.nextInt(max);
    }
    System.out.println("Array of random number is: ");
    for(int i=0;i<arr.length;i++){
    System.out.print(arr[i]+ " ");
    }
    insertionSort(arr);
    System.out.println("\nSorted array is: ");
    for(int i=0;i<arr.length;i++){
        System.out.print(arr[i]+ " ");
    }
    System.out.println();
    System.out.print("\nEnter an element to search: ");
    n=sc.nextInt();
    List<Integer> list = new ArrayList<Integer>();
    for (int i = 0; i < arr.length; i++){
        list.add(arr[i]);
    }
    System.out.println("The element is at position: "+(Collections.binarySearch(list, n)+1));
    }
}

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Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

I'd like to know the algorithmic complexity (Big O) of the project below:

import java.util.Random;
import java.util.*;
public class main{
    static void insertionSort(int arr[]){
        int n = arr.length;
        for (int i = 1; i < n; ++i){
            int key = arr[i];
            int j = i - 1;
            while (j >= 0 && arr[j] > key){
                arr[j + 1] = arr[j];
                j = j - 1;
            }
            arr[j + 1] = key;
        }
    }
public static void main(String[] args){
    int max = 100;
    int min = 1;
    int arr[]=new int[10];
    int n;
    @SuppressWarnings("resource")
    Scanner sc=new Scanner(System.in);
    Random randomNum = new Random();
    for(int i=0;i<arr.length;i++){
    arr[i] = min + randomNum.nextInt(max);
    }
    System.out.println("Array of random number is: ");
    for(int i=0;i<arr.length;i++){
    System.out.print(arr[i]+ " ");
    }
    insertionSort(arr);
    System.out.println("\nSorted array is: ");
    for(int i=0;i<arr.length;i++){
        System.out.print(arr[i]+ " ");
    }
    System.out.println();
    System.out.print("\nEnter an element to search: ");
    n=sc.nextInt();
    List<Integer> list = new ArrayList<Integer>();
    for (int i = 0; i < arr.length; i++){
        list.add(arr[i]);
    }
    System.out.println("The element is at position: "+(Collections.binarySearch(list, n)+1));
    }
}

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