Determine the affect of spectator ions on the pH of a solution of a weak acid. a. What is the pH of a 0.0200 M benzoic acid (Ka = 6.28 x 10-5) solution in water? b. What is the % dissociation of the benzoic acid in pure water? c. If the benzoic acid is dissolved in 0.10 M CaCl2 instead of pure water: Calculate the ionic strength of the solution (assume that the contribution from the benzoic acid is negligible).
Please help with parts d and e ASAP!!! Thank you and will rate back!!
Determine the affect of spectator ions on the pH of a solution of a weak acid.
a. What is the pH of a 0.0200 M benzoic acid (Ka = 6.28 x 10-5) solution in water?
b. What is the % dissociation of the benzoic acid in pure water?
c. If the benzoic acid is dissolved in 0.10 M CaCl2 instead of pure water: Calculate the ionic strength of the solution (assume that the contribution from the benzoic acid is negligible).
d. Now set up the equilibrium expression with the activities of the ions. Calculate the concentration of both the H+ and the benzoate ion. What is the pH of this solution? What is the % dissociation?
e. By what % did the benzoic acid dissociation change between the pure water solution and the calcium chloride solution?
![Que 6
(a) Gi ven,
C= 0.02 M
Ka= 6:28X10-5
Ph COOH = PhCo0
t=0
Cd.
t=ta c-Ca
Ka= Ca) Ca)
(C-Ca.)
Ka = _ca?
|-ベ.
ka = ca?
d= Ka
うペ=
6-28X10-5
0.02
> 2= 0.056
っ[ht] = Ca
= 0.02X 0.056
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