Draw and label the energy profile for a reaction that is summarized by the mechanism: Step 1: Cl2 + FeCl3 ⬄ Cl+ + FeCl4- Fast Step 2: C6H6 + Cl+ ? C6H6Cl+ Slow Step 3: C6H6Cl+ + FeCl4- ? C6H5Cl + FeCl3 +HCl Fast b) Write the overall equation for the reaction. Derive the rate law, assuming that the ratio [FeCl3]/ [FeCl4-] equals a constant, β. c) Write the overall equation for the reaction. Derive the rate law, assuming that the ratio [FeCl3]/ [FeCl4-] equals a constant, β.
Draw and label the energy profile for a reaction that is summarized by the mechanism: Step 1: Cl2 + FeCl3 ⬄ Cl+ + FeCl4- Fast Step 2: C6H6 + Cl+ ? C6H6Cl+ Slow Step 3: C6H6Cl+ + FeCl4- ? C6H5Cl + FeCl3 +HCl Fast b) Write the overall equation for the reaction. Derive the rate law, assuming that the ratio [FeCl3]/ [FeCl4-] equals a constant, β. c) Write the overall equation for the reaction. Derive the rate law, assuming that the ratio [FeCl3]/ [FeCl4-] equals a constant, β.
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter18: Chemical Kinetics
Section: Chapter Questions
Problem 22P
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(a) Draw and label the energy profile for a reaction that is summarized by the mechanism:
Step 1: Cl2 + FeCl3 ⬄ Cl+ + FeCl4- Fast
Step 2: C6H6 + Cl+ ? C6H6Cl+ Slow
Step 3: C6H6Cl+ + FeCl4- ? C6H5Cl + FeCl3 +HCl Fast
b) Write the overall equation for the reaction. Derive the rate law, assuming that the ratio [FeCl3]/ [FeCl4-] equals a constant, β.
c) Write the overall equation for the reaction. Derive the rate law, assuming that the ratio [FeCl3]/ [FeCl4-] equals a constant, β.
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