During laboratory testing of an 6-inch aluminum-alloy rod with a cross sectional area of 0.32in², a tensile load of 50,000lbs.is applied. Ifthe cross sectional area decreases to 0.3188in? and lengthens to 6.022 inches, what is the Modulus of Elasticity and Poisson's Ratio? Fall 2 erlag E = 6/ɛ V = = -E(lateral)/ɛ(axial)

Steel Design (Activate Learning with these NEW titles from Engineering!)
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Chapter1: Introduction
Section: Chapter Questions
Problem 1.5.6P: The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular...
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During laboratory testing of an 6-inch aluminum-alloy rod with a cross sectional
area of 0.32in², a tensile load of 50,000 lbs.is applied. Ifthe cross sectional area
decreases to 0.3188in? and lengthens to 6.022 inches, what is the Modulus of
Elasticity and Poisson's Ratio?
E = 6/ɛ
V =
= -E(lateral)/ɛ(axial)
Transcribed Image Text:During laboratory testing of an 6-inch aluminum-alloy rod with a cross sectional area of 0.32in², a tensile load of 50,000 lbs.is applied. Ifthe cross sectional area decreases to 0.3188in? and lengthens to 6.022 inches, what is the Modulus of Elasticity and Poisson's Ratio? E = 6/ɛ V = = -E(lateral)/ɛ(axial)
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