effective stress (kPa) at the base of each soil layer listed below. Assume the water table rest 4 m below ground surface and that there is a capillary rise of 1 m above the water table. Provide your answers in kPa to 1 decimal place. Use 9.81 kN/m3 as the unit weight of water. Total Neutral Effective Silty Sand: 5m thick, γt = 17.5 kN/m3, γsat = 18.5 kN/m3, Blank 1 Blank 2 Blank 3 Clay: 4m thick, γt = 16.5 kN/m3, γsat = 17.8 kN/m3, Blank 4 Blank 5 Blank 6 Sand: 6m thick, γt = 17.3 kN/m3, γsat = 18.1 kN/m3, Blank 7 Blank 8 Blank 9

effective stress (kPa) at the base of each soil layer listed below. Assume the water table rest 4 m below ground surface and that there is a capillary rise of 1 m above the water table. Provide your answers in kPa to 1 decimal place. Use 9.81 kN/m3 as the unit weight of water. Total Neutral Effective Silty Sand: 5m thick, γt = 17.5 kN/m3, γsat = 18.5 kN/m3, Blank 1 Blank 2 Blank 3 Clay: 4m thick, γt = 16.5 kN/m3, γsat = 17.8 kN/m3, Blank 4 Blank 5 Blank 6 Sand: 6m thick, γt = 17.3 kN/m3, γsat = 18.1 kN/m3, Blank 7 Blank 8 Blank 9

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter9: In Situ Stresses

Section: Chapter Questions

Problem 9.4P

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A saturated clay layer has a thickness of 10 meters with a water content of 51% and a specific gravity 2.72. Determine the following: 1. Saturated unit weight of the clay * a. 21.46 kN/m³ b. 18.12 kN/m³ c. 16.87 kN/m³ d. 14.95 kN/m³ 2. total stress at depth of 10 meters a. 122.1 kPa b. 151.3 kPa c. 168.7 kPa d. 142.5 kPa 3. Effective stress at depth of 10 meters a. 42.1 kPa b. 70.6 kPa c. 68.7 kPa d. 82.5 kPa
A uniform soil deposit has a dry unit weight of 15.6 kN/m³ and a saturated unit weight of 17.2 kN/m³. The groundwater table is at a distance of 4 m below the ground surface. Point A is at a depth of 6 m below the ground surface. If the water table rises by 3.5 m, determine the change in effective stress at A. Indicate if it is maintained, increased or decreased.
A soil profile consists of a sand layer underlain by a clay layer, as shown. If the degree of saturation of the sand above water table was 50%. Saturated and dry unit weight of sand are 21.2 kN/m^3 and 18.22 kN/m^3 respectively. The saturated unit weight of clay is 18 kN/m3. Determine the total stress, pore pressure and effective stress at point A,B,C.
A rectangular footing (4.14 x 4.43 m) is placed 1.38 m below the ground surface. The soil arrangement is composed of sand (ground) for the first 6.29 m and followed by clay for the next 5.94 m. The force acting on the footing is 10581 kN. Determine the resulting stress increase at the midheight of the consolidating layer in kPa. Assume 2V:1H pressure diagram. Unit weight of sand = 16.8 kn/m3. Unit weight of clay = 18.4 kn/m3
A rectangular footing (4.5 x 4.36 m.) is placed 1.98 m. below the ground surface. The soil arrangement is composed of sand (ground) for the first 6.94 meters and followed by clay for the next 6.78 meters. The force acting on the footing is 10,700 kN. Determine the settlement of the consolidating layer in mm. Assume a 2V:1H pressure diagram. Unit weight of sand = 16.9 kN/m3. Clay has the following properties: Unit weight = 18.3 kN/m3, Void ratio = 95, Liquid limit = 49. Round off to two decimal places.
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A soil profile consisting of three layers is shown in Table and Figure below i. Calculate the values of σ, u and σʹ at points A, B, C, and D. ii. Calculate the effective stress at c when water table drops by 1 m (consider γb= 15.5 for layer 2). iii. Calculate the effective stress at c when water table rises by 1 m above layer 1 due to flooding. (consider γsat= 16.5 for layer 1). Layer no. Thickness Soil parameters 1 H1 = 3.5 m γd = 15.5 kN/m3 2 H2 = 2.5 m γsat = 18 kN/m3 3 H3 = 3 m γsat = 18.5 kN/m3
A)Plot graphically all the vertical stresses, pore water and effective vertical stresses throughout the depth. B)How would the effective vertical stress value at the midpoint of the clay layer change if the groundwater level increased 2 m? (g = 10 m / s2)
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A dense silt has the following properties: Void ratio (e) = 0.40, SpecificGravity (Gs) = 2.70, Effective diameter d10 = 1x10^-6 m, Capillary constant (C) = 0.20 cm^2. Free ground water level is 8.0 m below the ground surface. a. Find the height of capillary rise in the silt. b. Find the vertical effective stress in kPa at 5m depth. Assume that the soil abovethe capillary zone or capillary action rise to be dry soil and the soil within thecapillary action be partially saturated (degree of saturation, S) at 50%. c. Find the vertical effective stress at 10m depth. Assume that the soil above thecapillary zone or capillary action rise to be dry soil and the soil within the capillaryaction be partially saturated (degree of saturation, S) at 50%.
For the layered soil shown in the figure, H1 = 5 m, H2 = 5 m, and H3 = 20 m. The soil densities are ρ1=2040kg/m3, ρ2=1940kg/m3, and ρ3′=1020kg/m3. What is the effective stress at the bottom of soil 3 when h' = 15 meters? CHOICES A. 142.7 kPa B. 150.1 kPa C. 163.8 kPa D. 136.8 kPa What value of h' will cause quick condition at the bottom of soil 3? CHOICES A. 30.3 m B. 25.4 m C. 20.8 m D. 33.3 m

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	Total	Neutral	Effective
Silty Sand: 5m thick, γ_t = 17.5 kN/m³, γ_sat = 18.5 kN/m³,	Blank 1	Blank 2	Blank 3
Clay: 4m thick, γ_t = 16.5 kN/m³, γ_sat = 17.8 kN/m³,	Blank 4	Blank 5	Blank 6
Sand: 6m thick, γ_t = 17.3 kN/m³, γ_sat = 18.1 kN/m³,	Blank 7	Blank 8	Blank 9