In the following figure(Figure 1), R1 =6.00 , Ra = 6.00 , and R3=6.00 2. The battery has negligible internal resistance. The currentIa through Rg is 5.00 APart AWhat is the current I, through R1?Express your answer with the appropriate units.HAI =ValueASubmitRequest AnswerFigureK 1 of 1Part BWhat is the current Iz through R3?R1Express your answer with the appropriate units.R2HA?I3 =ValueAR3SubmitRequest Answer近 Part CWhat is the emnf of the battery?Express your answer with the appropriate units.ValueVSubmitRequest AnswerProvide Feedback

Answered: Image /qna-images/answer/bedb5997-4b87-49ba-b0d7-3a1e914da059.jpg

Answered: In the following figure(Figure 1), R1…

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter27: Service-entrance Equipment

Section: Chapter Questions

Problem 44R

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Two metallic terminals protrude from a device. The terminal on the left is the positive reference for a voltage called Vx (the other terminal is the negative reference). The terminal on the right is the positive reference for a voltage called Vy (the other terminal being the negative reference). If it takes 1 mJ of energy to push a single electron into the left terminal, Determine the voltages Vx and Vy.
choose the correct answer 1. 3 amps flow through a 1 Ohm resistor. What is the voltage?(A) 1V (B) (C)3V (D)None of the above.2. Why do we say the "voltage across" or "the voltage with respect to?" Why can't we just sayvoltage?(A) Voltage is a measure of Electric Potential difference between two electrical points.(B) It's an Electrical Gliche.(C) The other point could be Negative or positive.(D) None of the above.3. A resistor consumes 5 watts, and its current is 10 amps. What is its voltage?(A) 10V (B)0.5V (C)2V (D)15V4. A resistor has 10 volts across it and 4 amps going through it. What is its resistance?(A) 2.5Ω (B)3.5Ω (C)4.5Ω (D) None of the above5. If you plot voltage vs. current in a circuit, and you get a linear line, what is thesignificance of the slope?(A)Power (B) Discriminant (C)Resistance (D)None of the above.6. A resistor has 8 volts across it and 3 Amps going through it. What is the powerconsumed?(A)24W (B)3W (C)8W…
The efficiency for incandescent light bulbs is typically about 14 lumens per watt (lm/W) and that for LED bulbs is typically about 90 lm/W. Use Ohm’s law to calculate the total light output in lumens of each type of bulb if the incandescent bulb has resistance of 10 Ω and the LED bulb has resistance of 2 Ω and each are supplied with a current of 2 A. Question 1 options: Incandescent: 230 lm. LED: 360 lm. Incandescent: 7840 lm. LED: 64800 lm. Incandescent: 112 lm. LED: 3600 lm. Incandescent: 560 lm. LED: 720 lm.
The following equations describe an electric circuit: -I1 (220 Ω) + 5.80 V - I2 (370 Ω) = 0 -I2 (370 Ω) + I3 (150 Ω) - 3.10 V = 0 I1 + I3 - I2 = 0(a) Draw a diagram of the circuit. (b) Calculate the unknowns and identify the physical meaning of each unknown.
Two batteries have each been measured with the following data: E1 = 33.6 V, R1 = 2.2 Ω E2 = 24 V, R2 = 1 Ω The batteries are then connected according to the picture below. Start by writing an equation where the sum of all voltages (ie both the voltages of the sources and the voltage drop across the resistors) is equal to zero. Note! The batteries are oppositely connected, i.e. the currents they drive counteract each other and then E1 and E2 in the equation must be of opposite signs. If you choose the clockwise direction then E1 is positive and E2 is negative. Voltage drops across the resistors are always negative -I(*R1) and -(I*R2). Add up all the voltages in the circuit and equate the sum to zero (Note: the equal sign and the zero are already written, complete the equation with the rest): a) Calculate the current flowing through the circuit. b) Calculate the voltage UAB. c) What is the direction of the current in the circuit:
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The circuit shown in the figure below is connected for 1.50 min. (Assume R1 = 6.50 Ω, R2 = 1.50 Ω, and V = 13.0 V.) A circuit is comprised of two adjacent rectangular loops that share a side such that the right side of the left loop is also the left side of the right loop. The left side of the left loop contains a resistor R1. The top side of the right loop contains a 3.00 Ω resistor. The right side of the right loop contains a battery V oriented with the positive terminal above the negative terminal. A resistor R2 is above the battery. The shared side contains a 4.00 V battery oriented with the positive terminal above the negative terminal. A 1.00 Ω resistor is above the battery and a 5.00 Ω resistor is above the 1.00 Ω resistor. (a) Determine the current in each branch of the circuit. branch magnitude (A) direction left branch ---Select--- up down middle branch ---Select--- up down right branch ---Select--- up down (b) Find the energy delivered by each…
Subject: Circuits 1show your solution please
can you create a diagram of this circuit? resistance:220 ohm diode 1N4007 BC548B Transıstor 1.5 V battery(current source) Capacıtor 470uf 25V shock coil ( I made 15 and 30 wraps to feritte core)(ı do not know the value.)
An accurate representation of a thermistor curve between Resistance (ohm) and Temperature (0C) is generally given by 1/T=ao+a1 (ln ( R) )+a2( ln ( R)2)Where T is temperature in Kelvin, R is resistance in ohms, and ao,a1, a2 are constants of the curve. Given the following for a thermistor R(ohm) T(C) 120.98+4 68.654 134.01+4 45.978 170.224+44*4 35.127 For a measured resistance of 44^2+1.23 ohms, to find the value of temperature in 0C by using Gauss Elimination method.
A wire has a circular cross-section of radius r= 3.53 mm. The conductivity of the wire is 1x10^5 (Ohm, meter) and its lengthis 2m. The total resistance of the wire in Ohms is:O a. 0.51O b. 0.72ç. 0.26O d. 5136.07O e. 797497.60
subject:Circuits 1please this one too give me a slightly favor can you answer this questions please wanna learn more im having difficuilty about this questions

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