Excess iron in the body, or hemochromatosis,can cause serious cell damage. One way to treat excess iron build up is to administer small molecules with a high affinity for iron. The small molecules form a complex ion with the iron, thus allowing the iron to be excreted. One small molecule that could be used to treat excess iron, L (M = 598.60 gmol-1), is shown on the right. The reaction between Fe3+ and L is: Fe3+(aq)+?(aq)⇌ Fe?3+(aq) Kf =4.68×1025
Excess iron in the body, or hemochromatosis,can cause serious cell damage. One way to treat excess iron build up is to administer small molecules with a high affinity for iron. The small molecules form a complex ion with the iron, thus allowing the iron to be excreted. One small molecule that could be used to treat excess iron, L (M = 598.60 gmol-1), is shown on the right. The reaction between Fe3+ and L is: Fe3+(aq)+?(aq)⇌ Fe?3+(aq) Kf =4.68×1025
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 92QRT
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Excess iron in the body, or hemochromatosis,can cause
serious cell damage. One way to treat excess iron build up
is to administer small molecules with a high affinity for
iron. The small molecules form a complex ion with the
iron, thus allowing the iron to be excreted. One small
molecule that could be used to treat excess iron, L (M =
598.60 gmol-1), is shown on the right. The reaction
between Fe3+ and L is:
Fe3+(aq)+?(aq)⇌ Fe?3+(aq) Kf =4.68×1025
A 1.00L solution of 1.00 g/L of Fe3+(aq) has 1.00 mol of L added. What is the equilibrium
concentration of iron(III), (i.e.,[Fe3+]eq) in the final solution?
serious cell damage. One way to treat excess iron build up
is to administer small molecules with a high affinity for
iron. The small molecules form a complex ion with the
iron, thus allowing the iron to be excreted. One small
molecule that could be used to treat excess iron, L (M =
598.60 gmol-1), is shown on the right. The reaction
between Fe3+ and L is:
Fe3+(aq)+?(aq)⇌ Fe?3+(aq) Kf =4.68×1025
A 1.00L solution of 1.00 g/L of Fe3+(aq) has 1.00 mol of L added. What is the equilibrium
concentration of iron(III), (i.e.,[Fe3+]eq) in the final solution?
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