For a different reaction, K. = 103, kg = 6.76 x 10's1, and k, = 65.7 s. Adding a catalyst increases the forward rate constant to 9.73x105 s-1. What is the new value of the reverse reaction constant, k, after adding catalyst? Express your answer with the appropriate units. Include explicit multiplication within units, for example to enter M between each measurement. •s1 include - (multiplication dot) > View Available Hint(s) HA k, = Value s 1

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.99PAE: Substances that poison a catalyst pose a major concern for many engineering designs, including those...
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For a different reaction, K. = 103, kg = 6.76 x 10's, and k, = 65.7 s Adding a catalyst increases the forward rate constant to 9.73×105 s-1 What is the new
value of the reverse reaction constant, k, after adding catalyst?
Express your answer with the appropriate units. Include explicit multiplication within units, for example to enter M s include - (multiplication dot)
between each measurement.
> View Available Hint(s)
k, =
Value.
s 1
Transcribed Image Text:For a different reaction, K. = 103, kg = 6.76 x 10's, and k, = 65.7 s Adding a catalyst increases the forward rate constant to 9.73×105 s-1 What is the new value of the reverse reaction constant, k, after adding catalyst? Express your answer with the appropriate units. Include explicit multiplication within units, for example to enter M s include - (multiplication dot) between each measurement. > View Available Hint(s) k, = Value. s 1
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