Gaseous butane CH3CH22CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 4.65 g of butane is mixed with 25. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

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Asked Dec 3, 2019
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Gaseous butane 

CH3CH22CH3

 will react with gaseous oxygen 

O2

 to produce gaseous carbon dioxide 

CO2

 and gaseous water 

H2O

. Suppose 4.65 g of butane is mixed with 25. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

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Expert Answer

Step 1

Given,
4.65 g of butane mixed with 25.0 g of oxygen.

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The balancing equation for the combustion reaction is given below 13 0, (g)4CO, (g)+5H2Og) 2 C,H1 g)+ According to the balancing equation, one mole of butane reaction with 13/2 moles of oxygen gives four moles of carbon dioxide Moles of butane is calculated as follows Mass Moles 11 Molar mass 4.65g 58.12 g/mol Moles Moles 0.0800 mole

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Step 2

The required O2 is 0.52 mole, but according to the given reaction moles of oxygen is 0.7813 moles. Therefore but...

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Moles of oxygen is calculated as follows Mass Moles Molar mass 25g 32.0 g/mol Moles Moles 0.7813 mole According to the balancing equation, one mole of butane reaction with 13/2 moles of oxygen gives four moles of carbon dioxide Therefore Number of moles of oxygen for the reaction is given below 13 mol O2 2 Moles moles of butanex mol butane 13 mol O2 Moles 0.0800x-2 molbutane Moles 0.52 mole

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