Given: 3 Pt2+(aq) + 2 Cr(s) ⟶ 2 Cr3+(aq) + 3 Pt(s) Eo = +0.44 v [Cr3+] = 0.512 M, [Pt2+] = 0.00318 M Calculate the value of E. E = Eo - (0.0592/n) log Q Express the answer to 2 sig. figs.
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Given: 3 Pt2+(aq) + 2 Cr(s) ⟶ 2 Cr3+(aq) + 3 Pt(s)
Eo = +0.44 v
[Cr3+] = 0.512 M, [Pt2+] = 0.00318 M
Calculate the value of E.
E = Eo - (0.0592/n) log Q
Express the answer to 2 sig. figs.
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