Glucose-1-phosphate = glucose-6-phosphate AGo = - 7.3 kJ mol-1 Glucose-6-phosphate = fructose-6-phosphate AG'o = + 1.7 kJ mol-1 wwwm Calculate the equilibrium constant, K'eq, for the conversion of glucose-1-phosphate to fructose-6-phosphate. You can use a value of RT = 2.48 kJ mol-1. %3D

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section18.1: Spontaneity And Energy Transfer As Heat
Problem 2RC: A process that is reactant-favored at equilibrium can never be spontaneous. This statement is (a)...
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Glucose-1-phosphate = glucose-6-phosphate AG'o = - 7.3 kJ mol-1
Glucose-6-phosphate = fructose-6-phosphate AG'O = + 1.7 kJ mol-1
Calculate the equilibrium constant, K'eg, for the conversion of glucose-1-phosphate to
fructose-6-phosphate. You can use a value of RT = 2.48 kJ mol-1.
Transcribed Image Text:Glucose-1-phosphate = glucose-6-phosphate AG'o = - 7.3 kJ mol-1 Glucose-6-phosphate = fructose-6-phosphate AG'O = + 1.7 kJ mol-1 Calculate the equilibrium constant, K'eg, for the conversion of glucose-1-phosphate to fructose-6-phosphate. You can use a value of RT = 2.48 kJ mol-1.
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