H2C=CHCH=CH2H2NCH,CH2CH2CH2CH2CH,NH2Reagentsa. Br2, CH2CI2КCN, HCNb.LIAIH, then H3o*H2, Pd/Cexcess NBS, CCI4excess CH3MgBr, ether then H3O*H3O*, heatC.d.е.f.g.Select reagents from the table to carry out this transformation.(Enter your answer as a single string of letters representing the reagents in the order that you wish to use them, i.e. bdce.)

H2C=CH-CH=CH2 (a) Br2CH2Cl2 → Br-H2C-CH=CH-CH2-Br

H2C=CHCH=CH2 H2NCH2CH2CH2CH2CH,CH;NH2 Reagents a. Br2, CH2CI2 КCN, HCN b. LIAIH, then H3o* d. H2, Pd/C excess NBS, CCI4 f. C. е. excess CH3MgBr, ether then H3O* H30*, heat g. Select reagents from the table to carry out this transformation. (Enter your answer as a single string of letters representing the reagents in the order that you wish to use them, i.e. bdce.)

H2C=CHCH=CH2 H2NCH2CH2CH2CH2CH,CH;NH2 Reagents a. Br2, CH2CI2 КCN, HCN b. LIAIH, then H3o* d. H2, Pd/C excess NBS, CCI4 f. C. е. excess CH3MgBr, ether then H3O* H30*, heat g. Select reagents from the table to carry out this transformation. (Enter your answer as a single string of letters representing the reagents in the order that you wish to use them, i.e. bdce.)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.29QAP

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