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Social ScienceDraw both resonance structures of the most stable carbocation intermediate in the reaction shown.
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HCI +
Expert Answer
The given compound is substituted diene. The reaction of diene with hydrochloric acid results in the formation of 1,2 product and 1,4 product.
In the first step, the double bond at 1st and 2nd position in a reactant abstracts a proton from the hydrochloric acid to yield tertiary and secondary carbocation intermediates as mentioned as I and II.
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CHз CH3 CH3 or Н—СІ CHз .CH3 .CHз II о- е
II carbocation intermediate is more stable because it is in conjugation with the double bond. The double bond shifts form 3rd and 4th position to 2nd and 3rd position a...
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CH3 CHз CHз 2 4CH3 .CH3 .CH3
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