Question
Asked Oct 29, 2019
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An initially 'compressed' spring (x1 = 0.4m) is observed to compress an additional 0.4 m before stopping and reversing the 26 m/s horizontal velocity of a 100 kg mass. Determine the spring constant in N/mm.
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Expert Answer

Step 1

Given:

Initial compression in the spring = 0.4 m

Additional compression in the spring = 0.4 m

Final compression in the spring = 0.8 m

Velocity of the block = 26 m/s

Mass of the block = 100 kg

Step 2

Calculating the spring cons...

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Applying work-energy theorem Work done by the spring force Change in kinetic energy of the block Initial kinetic energy of the block - x(100kg)x (27m / s) 36450J Final kinetic energy of the block at maximum compression = 0 J 0.8m Work done by spring force, W kx.dx 0.4m 0.8m k(0.8m) k(0.4m) W 2 2 l0.4m W 0.24k Joules (Work is negative as the force is oppo site to the direction of displacement) According to work-energy theorem 0.24k Final kinetic energy - Initial kinetic energy -0.24k 0-36450J 36450 N/m 151875 N/ m 0.24 k=151.875 N/mm

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