How many grams of Br, are needed to form 65.7 g of AIBR, ? 2 Al(s) + 3 Br, (1) 2 AIBR, (s) Step 1: Show the strategy for solving this problem. - grams Br, grams AIBr, Answer Bank moles Br grams Al grams AIBr, grams Br. moles AIBr, moles Al Step 2: Show the conversions required to solve this problem and calculate the grams of Br,. Step 2: Show the conversions required to solve this problem and calculate the grams of Br,. 65.7 g AIBr, x = g Br, Answer Bank 26.98 g Al I mole Al 2 moles Al 159.80 g Br I mole Br 3 moles Br, 266.68 g AIBr, I mole AlBr 2 moles AlBr, 65.7 g AlIBr, x = g Br, Answer Bank 26.98 g Al I mole Al 2 moles Al 159 80 g Br. 1 mole Be 3 moles Br, 266.68 g AIBr, 1 mole AlBr 2 moles AlBr, g Br, grams of Br,:

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Polymerization Kinetics

Polymerization is a chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that diverge in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes. Polymerization is generally classified into step-growth and chain polymerization. Polymers are categorized into linear polymer and cross-linked polymers that are produced either by condensation or additional polymerization.