I need help calculating the last value using my zone average molarity of KMnO4K, 0.01366 M, and my calculated value for the average molarity of KMnO4, 0.0114809 M. Part 2. Determination of the Mass Percent of FeS0, • 7H,04.Experimental DataSample #_Pill #1Pill #21.0412g1,0393gMass of boat and ground pill0.6825g0.6632gMass of boatInitial burette reading27.0mL28.9 mLFinal burette reading44,2mL43.5mkReactionMnO, + 5 Fe?+ + 8 H* → 5 Fe + Mn² + 4 H,0Calculated ValuesUse your [KMNO,Jv = 0.0114809from Part 1%3DMass of ground pill0.35870.3711Volume of KMnO,17,214.6Moles of KMNO,0.000197470.000167621Moles of Fe2+0.0009873550.000838105Moles of FeSO, • 7H,O0,0009873550.000838105Mass of FeSO, • 7H,O0.2745000.233000Mass % FeSO, • 7H,076,526062.7863169.6561Average mass % FeSO, • 7H,OAdditional calculation (see page 4-7 and Worksheet)Average mass % FeSO, • 7H,O using zone [KMnO̟]4 Additional Calculation:instead of your [KMNO,]. TheThe results for Part 2 could be recalculated using the [KMN0,]cne averageformula below will give the average mass percent of FeSO, • 7H,O using the zone average [KMNO¸],without repeating all the calculations. Show your work.[KMNO (zone)%3D(zone KMNO4)[KMNO (yours)Avg mass % FeSO, • 7H,O4one KMnO,) = Avg mass % FeSO, • 7H,Oyour KMnO,)(your KMNO4)

The formula to be used in the additional calculation involves the following quantities. Avg mass %…

Answered: I need help calculating the last value…

I need help calculating the last value using my zone average molarity of KMnO4K, 0.01366 M, and my calculated value for the average molarity of KMnO4, 0.0114809 M

Chemistry: Matter and Change

1st Edition

ISBN:9780078746376

Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Chapter19: Redox Reactions

Section: Chapter Questions

Problem 95A

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Question

I need help calculating the last value using my zone average molarity of KMnO4K, 0.01366 M, and my calculated value for the average molarity of KMnO4, 0.0114809 M.

Part 2. Determination of the Mass Percent of FeS0, • 7H,0
4.
Experimental Data
Sample #_
Pill #1
Pill #2
1.0412g
1,0393g
Mass of boat and ground pill
0.6825g
0.6632g
Mass of boat
Initial burette reading
27.0mL
28.9 mL
Final burette reading
44,2mL
43.5mk
Reaction
MnO, + 5 Fe?+ + 8 H* → 5 Fe + Mn² + 4 H,0
Calculated Values
Use your [KMNO,Jv = 0.0114809
from Part 1
%3D
Mass of ground pill
0.3587
0.3711
Volume of KMnO,
17,2
14.6
Moles of KMNO,
0.00019747
0.000167621
Moles of Fe2+
0.000987355
0.000838105
Moles of FeSO, • 7H,O
0,000987355
0.000838105
Mass of FeSO, • 7H,O
0.274500
0.233000
Mass % FeSO, • 7H,0
76,5260
62.78631
69.6561
Average mass % FeSO, • 7H,O
Additional calculation (see page 4-7 and Worksheet)
Average mass % FeSO, • 7H,O using zone [KMnO̟]
4

Additional Calculation:
instead of your [KMNO,]. The
The results for Part 2 could be recalculated using the [KMN0,]cne average
formula below will give the average mass percent of FeSO, • 7H,O using the zone average [KMNO¸],
without repeating all the calculations. Show your work.
[KMNO (zone)
%3D
(zone KMNO4)
[KMNO (yours)
Avg mass % FeSO, • 7H,O4one KMnO,) = Avg mass % FeSO, • 7H,Oyour KMnO,)
(your KMNO4)

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