ICP is used to monitor a solution of 10 000 mg/L as feed to a nanofilter membrane. After 30 min, 60 minutes and 120 minutes the permeate read as 10 g/L, 50 ppm and 45 ppm, respectively.
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Does it matter if we use ICP, AAS , IC or UV Vis if the solution was MgCl2
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- Standardization of Sodium Thiosulfate Solution Primary Standard used: Potassium Dichromate Formula mass of 1o standard: __________________ % Purity of 1o standard: 99.80% Trials 1 2 3 Weight of K2Cr2O7 (g)Weight of K2Cr2O7 (g) 0.0315 0.0331 0.0380 Final Volume Reading Na2S2O3 (ml) 27.50 27.50 34.90 Initial Volume Reading Na2S2O3 (ml) 1.10 0.00 1.00 Net Volume Na2S2O3 used (ml) Molarity of Na2S2O3The concentration of purified OXA-M290 is tested with a BCA assay. Serial dilutions of a bovine serum albumin (BSA) stock solution are prepared, then pipetted into a 96-well plate; each dilution of the BSA standard is tested in triplicate. Then, bicinchoninic acid and Cu2+ ions are added to all of the wells of the plate. After incubating the plate for 1 hour, a microplate reader is used to measure the absorbance of all of the wells in the plate at 560 nm. This generates the following data: BSA conc. (μg/mL), Replicate 1 Absorbance, Replicate 2 Absorbance, Replicate 3 Absorbance 40, 1.360, 1.403, 1.481 20, 0.750, 0.745, 0.810 10, 0.380, 0.344, 0.398 5, 0.198, 0.160, 0.183 2.5, 0.090, 0.100, 0.085 1.25, 0.038, 0.043, 0.051 0.625, 0.024, 0.028, 0.019 Prepare a calibration curve using these data. You can use Excel, R, SPSS or an equivalent graphing software. In this graph, plot absorbance (y-axis) against the concentration of the protein standard (x-axis). Calculate and plot…A 60-year-old woman who weighs 75kg requires a loading dose of an antibiotic to treat an infection. A plasma concentration of 4.5 mg/L of the antibiotic needs to be achieved for optimal therapeutic effectiveness. The volume of distribution (Vd) of this antibiotic is 0.2 L/kg. The salt factor (S) is 0.6 and bioavailability fraction (F) is 1. The antibiotic is available as a 100 mg/mL infusion.Loading dose = Amount of drug in the bodyBioavailability (F) x Salt fraction (S)Amount of drug in the body = Target conc. (C) x Volume of distribution (Vd)How many millilitres of antibiotic infusion need to be administered?State your answer to 1 decimal place.unit- ml
- A 5.000-g soil sample was analyzed for potassium content by extracting the potassium using 10.00 mL aqueous ammonium acetate solution. Following the extraction, the soil was filtered and rinsed. The filtrate with rinsings was diluted to exactly 50.00 mL. Then, 1.00 mL of this solution was diluted to 25.00 mL, and this dilution was tested with an instrument. The concentration in this 25.00 mL was found to be3.18 ppm. What is the concentration of the potassium in the soil in ppm?1. Samples that should not be stored should be prepared/analyzed as soon as possible, especially for measurement…a. hardnessb. Nitritec. Conductivityd. Phenol 2. The following are general sample treatments in pesticide analysis, except…a. Extractionb. Cleaningc. Concentrationd. FilteringA 25.00mL wastewater sample was analyzed for its Mg2+ content using a standard gravimetric method. the sample was diluted to 3.00L and an 11.00mL aliquot was treated to precipitate magnesium as MgNH4PO4.6H2O using (NH4)2HPO4 as the precipitating agent. the precipitate was then filtered, washed, dried, and ignited resulting in a 0.1325mg Mg2P2O7 residue. How much Mg (in ppm) is present in the original sample
- Six clean, dry, 18 x 150mm test tubes 1-6 was labeled. 5.00 L of 2.00 x 10-3 M Fe(NO3)3 solution was pipeted in each tubes. Then 1.00,2.00,3.00,4.00, and 5.00 mL of 2.00 x 10-3 M of 2.00 x 10-3 M NaSCN solution was then added to test tubes 2-6 respectively. 5.00, 4.00 ,3.00,2.00 and 1.00 mL of 0.10 M HNO3 was then further added to test tubes 1-6 respectively. The total volume in each test tube is 10 mL. a) what is the concentration of Fe(NO3)3 in 0.10 M HNO3? b) what is the concentration of NaSCN in 0.10 M HNO3 solution?The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463You are required to prepare working standard solutions of 1.00 × 10−5, 2.00 × 10−5, 5.00 × 10−5, and 1.00 × 10−4 M glucose from a 0.100 M stock solution. You have available 100-mL volumetric flasks and pipets of 1.00-, 2.00-, 5.00-, and 10.00-mL volume. Outline a procedure for preparing the working standards.
- A 100 g soil containing 20% smectitie mineral matter was mixed with 150 mL solution containing 0.10 M Pb. CEC of pure smectitie is 110 emol(+)/kg. CEC of the soil (cmol(+)/kg) is:hjhdg with solution sdfBlank determinations reveal errors due to interfering contaminants from the reaagents and vessels employed in the analysis.
