If 94.92 mL of a solution of HCI are equivalent to 43.76 mL of a solution of NaOH and if 49.14 mL of the latter will neutralize 0.2162 g of KHC2O4 · H2C2O4 • H2O. What volume of water should be added to a liter of the acid in order to make it 0.5050 normal?

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