4 20PROBLEM 8If anhydrous platinum(II) bromide is suspended inchloroform and treated with o-styryldimethyl arsine(o-S), three compounds, A, B and C can be isolated. ALLcompounds are monomeric and non-conducting in nitro-benzene. Formulae and infrared data are tabulated below:CH=CH2Vc=c/ cm-1o-S1630As (CH3)2PtBr, (o-S)21630APtBr, (o-S)21627BCPtBr, (o-S)1488Addition of an excess of bromine to A or B gave anorange complex, D, PtBr, (o-S), in which the bands at1630/1627 cm- were absent, but new bands had appearedat 594 and 572 cm-. Suggest structures for A, B, C,and D.

If anhydrous platinum(II) bromide is suspended in chloroform and treated with o-styryldimethyl arsine (o-S), three compounds, A, B and C can be isolated. ALL compounds are monomeric and non-conducting in nitro- benzene. Formulae and infrared data are tabulated below: CH=CH2 Üc=c/ cm-1 o-S 1630 As (CH3)2 A PtBr,(o-S), 1630 B PtBr,(o-S)2 1627 C PtBr, Co-S) 1488 Addition of an excess of bromine to A or B gave an orange complex, D, PtBr, (o-S), in which the bands at 1630/1627 cm- were absent, but new bands had appeared at 594 and 572 cm-. Suggest structures for A, B, C, and D.

If anhydrous platinum(II) bromide is suspended in chloroform and treated with o-styryldimethyl arsine (o-S), three compounds, A, B and C can be isolated. ALL compounds are monomeric and non-conducting in nitro- benzene. Formulae and infrared data are tabulated below: CH=CH2 Üc=c/ cm-1 o-S 1630 As (CH3)2 A PtBr,(o-S), 1630 B PtBr,(o-S)2 1627 C PtBr, Co-S) 1488 Addition of an excess of bromine to A or B gave an orange complex, D, PtBr, (o-S), in which the bands at 1630/1627 cm- were absent, but new bands had appeared at 594 and 572 cm-. Suggest structures for A, B, C, and D.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter26: Molecular Absorption Spectrometry

Section: Chapter Questions

Problem 26.17QAP

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