If one bit is mutated on the chromosome 11010001, which of the following chromosomes cannot be generated from the mutation operation? (There may be one or more correct answer(s), tick all that apply.) 11010111 11010011 O 11110000 O 11011001
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- Consider the following two wild type chromosomes: AB•CDEFGH I•JKLMN What kind of rearrangement is observed in the mutated chromosomes below? AB•CDEKLMNFGH I•J A. reciprocal translocation B. non-reciprocal translocation C. displaced duplication D. pericentric inversion E. paracentric inversionHere are the results of the testcross:Green-eyes, wild-type wings 245Green-eyes, miniature wings 232Wild-type eyes, wild-type wings 250Wild-type eyes, miniature wings 2386.) In your opinion, is the grn gene on the same chromosome as the min gene? How do you know?Next, you set up another experiment to determine if grn is on chromosome #1. The only appropriate fliesthat you have handy are double-mutants for the black-body mutation (blk) and curved wings mutation(crv), but this should work just fine. First, you conduct a series of crosses to generate a strain of triple-mutant flies (grn blk crv). Then, you cross those with wild-type flies to generate triple hybrids.7.) What are the genotype(s) and phenotype(s) of the progeny of this cross?Next, you set up a testcross to reveal any linkage between the three genes.8.) What are the genotypes and phenotypes of this testcross?A normal chromosome A B C D * E F G H I J K has mutated toA B C F E * D G H I J K J K.This is an example of a _________________ chromosomal mutation. ( * denotes the centromere) Group of answer choices Pericentric inversion of DEF and tandem duplication of JK. Pericentric inversion of DEF and displaced duplication of JK Paracentic inversion of DEF and displaced duplication of JK. Paracentric inversion of DEF and tandem duplication of JK.
- When a female melanotic fly is crossed with a normal male, the progeny are produced: 123 normal females, 125 melanotic females, and 124 normal males. In subsequent crosses between melanotic females and normal males, melanotic females are frequently obtained, but never any melanotic males. Provide a possible explanation for the inhertiacne of the melanotic mutation (Hint: The cross produces twice as many female progeny as male progeny)22q11.2 deletion syndrome, also called DiGeorge syndrome, causes atypical parathyroid glands, a heart defect, and an underdeveloped thymus gland. About 85 percent of patients have a microdeletion of part of chromosome 22. A girl, her mother, and a maternal aunt have very mild DiGeorge syndrome. They all have a reciprocal translocation of chromosomes 22 and 2. a. How can a microdeletion and a translocation cause the same symptoms? b. Why were the people with the translocation less severely affected than the people with the microdeletion? c. What other problems might arise in the family with the translocation?A chromosome initially has the following segments: A B • C D E F G Draw the chromosome, identifying its segments, that would result from each of the following mutations. a. Tandem duplication of DEF b. Displaced duplication of DEF c. Deletion of FG d. Paracentric inversion that includes DEFG e. Pericentric inversion of BCDE
- What kind of chromosome rearrangement (shown as ?) is represented below? a. insertion b. Pericentric inversion c. Robersonian translocation d. Paracentric inversion e. balanced translocationWhich type(s) of chromosomal aberrations result from chromosomal breaks on different chromosomes? Assume that a heterozygote for the aberration is viable. Select all correct answers. A.)Robertsonian translocation B.)reciprocal translocation C.)tandem duplication D.)paracentric inversion E.)pericentric inversion F.)large deletion. For the following types of chromosomal rearrangements,would it theoretically ever be possible to obtain aperfect reversion of the rearrangement? If so, wouldsuch revertants be found only rarely, or would theybe relatively common?a. A deletion of a region including five genesb. A tandem duplication of a region including five genesc. A pericentric inversiond. A Robertsonian translocatione. A mutation caused by a transposable elementjumping into a protein-coding exon of a gene
- You have identified a SNP marker that in one largefamily shows no recombination with the locus causinga rare hereditary autosomal dominant disease.Furthermore, you discover that all afflicted individuals in the family have a G base at this SNP on theirmutant chromosomes, while all wild-type chromosomes have a T base at this SNP. You would like tothink that you have discovered the disease locus andthe causative mutation but realize you need to consider other possibilities.a. What is another possible interpretation of the results?b. How would you go about obtaining additional genetic information that could support or eliminateyour hypothesis that the base-pair difference is responsible for the disease?Familial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior history of the disease. Consider the following pedigree (the darkly colored symbols represent affected individuals): a. Circle the individual(s) in which the mutation most likely occurred. b. Is the person who is the source of the mutation affected by retinoblastoma? Justify your answer. c. Assuming that the mutant allele is fully penetrant, what is the chance that an affected individual will have an affected child?A chromosome initially has the following segments:A B • C D E F G Draw the chromosome, identifying its segments, that would result from the following mutations. Q. Tandem duplication of DEF