If the signed integer in AX is greater than the signed integer in CX, then the code should go to the label L2.
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If the signed integer in AX is greater than the signed integer in CX, then the code should go to the label L2.
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- Write a C++ application to accept 20 numbers from the user. Find; a. arithmetic mean b. standard deviation c. varianceThe signed integer in AXE must be bigger than the integer in CX, hence your programme must have instructions to jump to label L2 in that case.The output printed after executing the following C++ code is Blank 1. int ex=95, ct ; switch (ex % 16) { case 0 : case 1 :case 2 :case 3: cout << 2*(ex/16) << endl ; break; case 4 : case 5 :case 6 :case 7: cout << 2*(ex/10) << endl ; break; case 8 : case 9 :case 10 :case 11: cout << 2*(ex%10) << endl ; break; case 12 : case 13 :case 14 :case 15: cout << 4*(ex/16) << endl ; break; }
- Change the following infix expression to a postfix expression A*B+C*D (A+B)*(C–D) ((A+B)*C)–D A+B*(C–D/(E+F))Write the correct C# code and remove the errors in this code please. Also tell that where we can use such codesQ1 \ Convert the following infix expression into postfix one: (A+B^D)/(D-F)+G PS: you have to illustrate the different steps of this conversion one by one.
- In this chapter, you learned that although a double and a decimal both hold floating-point numbers, a double can hold a larger value. Write a C# program named DoubleDecimalTest that declares and displays two variables-a double and a decimal. Experiment by assigning the same constant value to each variable so that the assignment to the double is legal but the assignment to the decimal is not. In other words, when you leave the decimal assignment statement in the program, an error message should be generated that indicates the value is outside the range of the type decimal, but when you comment out the decimal assignment and its output statement, the program should compile correctly.USE C PROGRAMMING You need to print from a range of two inputted numbers, n1 and n2 (inclusive), all the even numbers from n2 down to n1, in descending order. Example: Input 2 10 Output 10 8 6 4 2In this part, you need to convert the following C statement into MIPS int a = 8192, b = 65536, c = 17, x = 10, z; a |= b; z = 3*c + a*x; z -= a;