In a cohort of 5,000 individuals, ages 40-50 years of age, blood samples were collected at baseline and stored for future analysis. After five years of study, Vitamin D levels were determined among those who developed Multiple Sclerosis (MS) and those who did not develop MS. The following results were observed. Serum Level of Vitamin D Incident Cases of MS Healthy Entire Cohort Individuals Above 40 ng per ml 2 1998 2000 20-40 ng per ml 4 1996 2000 Below 20 ng per ml 4 996 1000 If Vitamin D assays cost $20 per specimen, what is the total cost of these assays in the cohort study
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- Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on organisms, an expert claimed that the amount of gamma radiation needed to sterilize a colony of tardigrades no longer has a mean of 900 Gy (grays). (For comparison, humans cannot withstand more than 10 Gy .) A study was conducted on a sample of 27 randomly selected tardigrade colonies, finding that the amount of gamma radiation needed to sterilize a colony had a sample mean of 907 Gy , with a sample standard deviation of 17 Gy . Assume that the population of amounts of gamma radiation needed to sterilize a colony of tardigrades is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that μ , the mean amount of gamma radiation needed to sterilize a colony of tardigrades, is not equal to 900…Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on organisms, an expert claimed that the amount of gamma radiation needed to sterilize a colony of tardigrades no longer has a mean of 900 Gy (grays). (For comparison, humans cannot withstand more than 10 Gy .) A study was conducted on a sample of 27 randomly selected tardigrade colonies, finding that the amount of gamma radiation needed to sterilize a colony had a sample mean of 907 Gy , with a sample standard deviation of 17 Gy . Assume that the population of amounts of gamma radiation needed to sterilize a colony of tardigrades is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that μ , the mean amount of gamma radiation needed to sterilize a colony of tardigrades, is not equal to 900…A heart study objective was to study heart disease among healthy volunteers.After a 10-year follow-up period involving men aged 40 to 59, there were 16 casesof coronary heart disease (CHD) among the 454 men who initially had cholesterollevels below 210 mg/100 ml (referred to as the low serum cholesterol group). Incontrast, among the 424 men whose initial cholesterol levels were at least 245mg/100 ml (referred to as the high serum cholesterol group), there were 51 cases ofCHD. With this information, Draw a 2x2 contingency table then calculate the relative risk (RR) associated with high serum cholesterol and provide an interpretation of the result.
- Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on organisms, an expert claimed that the amount of gamma radiation needed to sterilize a colony of tardigrades no longer has a mean of 1350 Gy (grays). (For comparison, humans cannot withstand more than 10 Gy .) A study was conducted on a sample of 18 randomly selected tardigrade colonies, finding that the amount of gamma radiation needed to sterilize a colony had a sample mean of 1375 Gy , with a sample standard deviation of 75 Gy . Assume that the population of amounts of gamma radiation needed to sterilize a colony of tardigrades is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that μ , the mean amount of gamma radiation needed to sterilize a colony of tardigrades, is not equal to 1350 Gy .In a cohort study of 300 members of the Men of Leisure Club who took a vacation to the Bahamas, 170 became infected with giardiasis. One hundred twenty nine (129) who swam in a resort pool became ill, and 94 who did not swim did not become ill. Set up the 2x2 table and calculate the appropriate rate of risk.To combat antibiotic resistance, the Quality Improvement Consortium recommends a throat swab to confirm strep throat before a physician prescribes antibiotics to children under age 5. Nationally, 40 percent of children under 5 who received antibiotics did not have a throat swab. The Colorado Department of Health took a random sample of 60 children under the age of 5 who received antibiotics for throat infections and found that 18 did not have a throat swab. At α = .05, is this a statistically significant reduction over last year’s national rate of 40 percent? (a-1) Calculate the critical value. (A negative value should be indicated by a minus sign. Round your answer to 3 decimal places.) Critical value _____ (a-2) Calculate the test statistic. (A negative value should be indicated by a minus sign. Round your answer to 2 decimal places.) Test statistic _____
- To combat antibiotic resistance, the Quality Improvement Consortium recommends a throat swab to confirm strep throat before a physician prescribes antibiotics to children under age 5. Nationally, 40 percent of children under 5 who received antibiotics did not have a throat swab. The Colorado Department of Health took a random sample of 100 children under the age of 5 who received antibiotics for throat infections and found that 30 did not have a throat swab. At α = .05, is this a statistically significant reduction over last year’s national rate of 40 percent? (a-1) Choose the correct null and alternative hypotheses. H0: π ≥ .40 vs. H1: π < .40 H0: π ≤ .40 vs. H1: π > .40 H0: π = .40 vs. H1: π ≠ .40 (a-2) Calculate the critical value. (A negative value should be indicated by a minus sign. Round your answer to 3 decimal places.) Critical value (a-3) Calculate the test statistic. (A negative value should be indicated by a minus sign. Round your…Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. The Czech and Slovak governments have set a safety limit for cadmium in dry vegetables at 0.5 part per million (ppm). M. Melgar et al. measured the cadmium levels in a random sample of the edible mushroom Boletus pinicola and published the results in the paper “Influence of Some Factors in Toxicity and Accumulation of Cd from Edible Wild Macrofungi in NW Spain” (Journal of Environmental Science and Health, Vol. B33(4), pp. 439–455). A hypothesis test is to be performed to decide whether the mean cadmium level in Boletus pinicola mushrooms is greater than the government’s recommended limit. Hypothesis tests are proposed. For each hypothesis test,a. determine the null hypothesis.b. determine the alternative hypothesis.c. classify the hypothesis test as two tailed, left tailed, or right tailed.Researchers at a medical school want to compare the rates of birth defects in babies born to mothers with low-fat diets with those born to mothers with high-fat diets. For one year, they collected data on all babies and their mothers in area hospitals, using information obtained from the mothers to determine whether they fall in the low fat or high fat diet category.A) Observational B) Experimental
- A manufacturer is developing a nickel-metal hydride battery to be used in cellular telephones instead of a nickel-cadmium battery. The director of quality control decides to evaluate the newly developed battery by picking a random sample of employees with cellular phones and asking them to use both phones until the batteries run down. The results are given in the excel data file. At the 5% level of significance is there evidence that the new battery provides more minutes of talk time per battery charge? Show your work and give your answer in complete sentences in context of the problem. Data Table: Person Old Battery Type New Battery Type 1 72.39 89.95 2 75.25 64.60 3 82.10 71.25 4 58.98 87.07 5 67.07 103.11 6 35.98 76.46 7 75.37 83.92 8 66.00 83.42 9 73.14 84.30 10 67.14 92.48 11 83.06 93.48 12 57.00 59.11 13 65.92 92.27 14 76.12 61.81 15 85.21 72.83 16 80.73 42.17 17 60.65 83.89 18 36.63 94.41 19 77.98 70.30 20 75.40 77.72 21 84.70 84.35…Rosner analyzed data from children who lived near a lead smelter (which is a facility that uses extreme heat to extract the metal lead from lead ore) in El Paso, Texas, and reported that out of 124 children studied, 23 developed colic (which is a pattern of fussiness and crying for no apparent reason). Suppose that in the state of Taxes in general at the time (early 1980s), the rate of colic in children was 16.0%. Follow the steps for testing whether the proportion of children developing clico was significantly different for the 124 children living near the lead smelter than for Taxes children in general (16%). Use alpha level of 0.03 a. Identify the null hypothesis for this statistical test. b. Identify the alternative hypotheses for this statistical test. c. Explain: Why should this be a two-tailed test, the way I have described it? d. calculate the sample proportion p̂, rounded to three decimal places. e. Calculate the appropriate test statistic, show all work. f. Based on…Since its removal from the banned substances list in 2004 by the World Anti-Doping Agency,caffeine has been used by athletes with the expectancy that it enhances their workout andperformance. However, few studies look at the role caffeine plays in sedentary females.Researchers at the University of Western Australia conducted a test in which they determined therate of energy expenditure (kilojoules) on 10 healthy, sedentary females who were nonregularcaffeine users. Each female was randomly assigned either a placebo or caffeine pill (6mg/kg) 60minutes prior to exercise. The subject rode an exercise bike for 15 minutes at 65% of theirmaximum heart rate, and the energy expenditure was measured. The process was repeated on aseparate day for the remaining treatment. The mean difference in energy expenditure (caffeine –placebo) was 18kJ with a standard deviation of 19kJ. If we assume that the differences follow anormal distribution can it be concluded that that caffeine appears to increase…