In a study of osteoporosis, bone density was measured in postmenopausal women. Women were chosen from the four major ABO blood groups and who had either had children or never gave birth. There were four women for each combination of blood group and childbearing status. Test for a significant differences in bone density due to childbearing status (factor A), blood group (factor B), and test for a significant interaction between childbearing status and blood group. Use a 5% level of significance for each test. Bone Density (g/cm^2) Childbearing Blood Group A В АВ 0.68 0.71 0.67 0.75 No children 0.77 0.67 0.71 0.74 0.72 0.76 0.69 0.88 0.81 0.66 0.73 0.67 0.83 0.82 0.73 0.71 Children 0.77 0.78 0.78 0.74 0.82 0.73 0.72 0.81 0.78 0.79 0.81 0.78 Use the table data above and the provided SS values to answer the following questions: SS, = 0.0938; SS, = 0.0190; SS, = 0.0088; SS, = 0.0070; SSg = 0.0589. Hint* See the lecture outline or class notes to calculate the degrees of freedom values on your own (df; df dfg; df; df). %3D Which of the following are the correct degrees of freedom values for this problem? a. df,= 32; df,= 3; df;= 3; df;= 4; df; = 31 b. df,= 31; df,= 3; df= 1; df,= 4; dfp = 21 c. df,= 31; df,= 1; df= 3; df;= 3; df = 24 d. df,= 32; df,= 1; df;= 1; df;= 3; df = 24 Which of the following terms represent the 3 calculated values? Hint* simply identify the calculated values for the two factor ANOVA that has factors A and B. You need to know what the subscripts A, B, E, I, T stand for. a. FA; FB; Fr b. FA; FE; Fr c. FA; Fp; F, d. FA; FB; FT What are your 3 calculated values corresponding to your answer in the previous question? а. 145.53; 53.76; 0.96 b. 7.75; 1.20%; 0.96 c. 0.96; 13.76; 15.53 d. 14.86; 6.53; 3.25

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In a study of osteoporosis, bone density was measured in postmenopausal women. Women were
chosen from the four major ABO blood groups and who had either had children or never gave
birth. There were four women for each combination of blood group and childbearing status. Test
for a significant differences in bone density due to childbearing status (factor A), blood group
(factor B), and test for a significant interaction between childbearing status and blood group. Use
a 5% level of significance for each test.
Bone Density (g/cm^2)
Childbearing
Blood Group
A
B
АВ
0.68
0.71
0.67
0.75
No children
0.77
0.67
0.71
0.74
0.72
0.76
0.69
0.88
0.81
0.66
0.73
0.67
0.83
0.82
0.73
0.71
Children
0.77
0.78
0.78
0.74
0.82
0.73
0.72
0.81
0.78
0.79
0.81
0.78
Use the table data above and the provided SS values to answer the following questions: SS,
0.0938; SS, = 0.0190; SS, = 0.0088; SS, = 0.0070; SS = 0.0589. Hint* See the lecture outline
or class notes to calculate the degrees of freedom values on your own (df,; df dfg; df; df).
%3D
%3D
Which of the following are the correct degrees of freedom values for this problem?
a. df,= 32; df,= 3; dfg= 3; df;= 4; df; = 31
b. df,= 31; df,= 3; df;= 1; df;= 4; dfg = 21
c. df,= 31; df= 1; df;= 3; df;= 3; df; = 24
d. df;= 32; df,=1; dfg= 1; df;= 3; df; = 24
Which of the following terms represent the 3 calculated values? Hint* simply identify the
calculated values for the two factor ANOVA that has factors A and B. You need to know what the
subscripts A, B, E, I, T stand for.
a. FA; FB; FT
b. FA; FE; Fr
c. FA; FR; F,
d. FA; FB; FT
What are your 3 calculated values corresponding to your answer in the previous
question?
a. 145.53; 53.76; 0.96
b. 7.75; 1.20%; 0.96
c. 0.96; 13.76; 15.53
d. 14.86; 6.53; 3.25
What are your 3 critical values corresponding to your answer in the previous question?
а. 3.07;B 3.07; 2.84
b. 4.26; 9.55; 4.32
с. 4.26; 3.49; 9.55
d. 4.26; 3.01; 3.01
What are your 3 conclusions? Sidenote* Be prepared to write interpretations for these conclusions
for the exam.
a. Reject H0;
b. Do Not Reject H0;
c. Do Not Reject HO;
d. Reject H0;
Do Not Reject H0;
Reject H0;
Do not Reject HỌ
Reject H0
Do Not Reject H0;
Reject H0
Reject H0
Reject H0;
Transcribed Image Text:In a study of osteoporosis, bone density was measured in postmenopausal women. Women were chosen from the four major ABO blood groups and who had either had children or never gave birth. There were four women for each combination of blood group and childbearing status. Test for a significant differences in bone density due to childbearing status (factor A), blood group (factor B), and test for a significant interaction between childbearing status and blood group. Use a 5% level of significance for each test. Bone Density (g/cm^2) Childbearing Blood Group A B АВ 0.68 0.71 0.67 0.75 No children 0.77 0.67 0.71 0.74 0.72 0.76 0.69 0.88 0.81 0.66 0.73 0.67 0.83 0.82 0.73 0.71 Children 0.77 0.78 0.78 0.74 0.82 0.73 0.72 0.81 0.78 0.79 0.81 0.78 Use the table data above and the provided SS values to answer the following questions: SS, 0.0938; SS, = 0.0190; SS, = 0.0088; SS, = 0.0070; SS = 0.0589. Hint* See the lecture outline or class notes to calculate the degrees of freedom values on your own (df,; df dfg; df; df). %3D %3D Which of the following are the correct degrees of freedom values for this problem? a. df,= 32; df,= 3; dfg= 3; df;= 4; df; = 31 b. df,= 31; df,= 3; df;= 1; df;= 4; dfg = 21 c. df,= 31; df= 1; df;= 3; df;= 3; df; = 24 d. df;= 32; df,=1; dfg= 1; df;= 3; df; = 24 Which of the following terms represent the 3 calculated values? Hint* simply identify the calculated values for the two factor ANOVA that has factors A and B. You need to know what the subscripts A, B, E, I, T stand for. a. FA; FB; FT b. FA; FE; Fr c. FA; FR; F, d. FA; FB; FT What are your 3 calculated values corresponding to your answer in the previous question? a. 145.53; 53.76; 0.96 b. 7.75; 1.20%; 0.96 c. 0.96; 13.76; 15.53 d. 14.86; 6.53; 3.25 What are your 3 critical values corresponding to your answer in the previous question? а. 3.07;B 3.07; 2.84 b. 4.26; 9.55; 4.32 с. 4.26; 3.49; 9.55 d. 4.26; 3.01; 3.01 What are your 3 conclusions? Sidenote* Be prepared to write interpretations for these conclusions for the exam. a. Reject H0; b. Do Not Reject H0; c. Do Not Reject HO; d. Reject H0; Do Not Reject H0; Reject H0; Do not Reject HỌ Reject H0 Do Not Reject H0; Reject H0 Reject H0 Reject H0;
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