In a study of the accuracy of fast food drive-through orders, Restaurant A had 317 accurate orders and 58 that were not accurate. a. Construct a 95% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 95% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.136
Q: The St. Lucie County Health Department needs to estimate the proportion of all children in the…
A: Note: As per my policy i can answer only three sub parts. kindly repost the remaining sub parts…
Q: To assess the effectiveness of a kindergarten-readiness program, 15 children from a random sample…
A:
Q: The following data were collected in a clinical trial to compare a new drug to a placebo for its…
A: Hello. Since your question has multiple parts, we will solve first question for you. If you want…
Q: A computer software magazine compares the rates of malware infection for computers protected by…
A: There are two independent samples which are software A and software B. Both samples are drawn from…
Q: Construct the requested confidence interval. In a Gallup Poll of 1005 individuals, 452 thought they…
A:
Q: The research group asked the following question of individuals who earned in excess of $100,000 per…
A:
Q: 4. The World Health Organization reports that in a sample of 10,013 people globally, 9 in 31 people…
A: We know, we calculate CI for a single proportion with the formula z*=1.96 for 95% 1.645 for…
Q: In a poll conducted by the Gallup organization in April 2013, 48% of a random sample of 1022 adults…
A: Obtain the 95% confidence interval for the proportion of all U.S. adults in April 2013 who felt that…
Q: The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.4 15 15.4 15.7…
A: According to the given information in this question We need to find margin of error
Q: 98% VaR that is acceptable in a 1-year backtest to conclude, at a 95% confidence level, that the…
A: The risk manager will reject the hypothesis that the model is correctly calibrated if the number X…
Q: The International Nanny Association (INA) reports that in a sample of 928 in- home child care…
A: Solution: A. Let X be the number of number of nannies who have passed the INA certification exam and…
Q: The production manager in an automobile plant is concerned with the number of cars that do not pass…
A:
Q: In an experiment of normal body temperatures in degrees Fahrenheit, 6 males ages 25-40 were given a…
A: a) The 95% confidence interval for body temperature of males ages 25-40 is calculated below:…
Q: The production manager in an automobile plant is concerned with the number of cars that do not pass…
A: Not acceptable = 120-92 = 28
Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…
A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…
Q: A telephone company has the business objective of wanting to estimate the proportion of households…
A:
Q: A &B
A: The provided data mentions the value of sample size, n is 928 and the value of x is 128. The…
Q: b. Construct a confidence interval suitable for testing the claim that the mean IQ scores for…
A: b. Here, medium lead level is the first sample and high-level lead is the second sample. The…
Q: 1. A poll of 2,500 people shows that 50% approve of a smoking ban in bars and restaurants. What is…
A:
Q: The St. Lucie County Health Department needs to estimate the proportion of all children in the…
A: It is given that the sample size (n) is 239 and the sample proportion is 0.67.
Q: In an article in Marketing Science, Silk and Berndt investigate the output of advertising agencies.…
A: Givenx=115n=390p^=xn=115390=0.2949confidence interval = 90%
Q: a. the incidence (%) of CHD among smokers: b. the incidence (%) of CHD among non-smokers: c. the RR…
A: Solution: a) The incidence rate of CHD among smokers here is computed as:= 180 / (3920 + 180) =…
Q: The following are body mass index (BMI) scores measured in 12 patients who are free of diabetes and…
A: Sample mean and sample standard deviation: Sample mean and sample standard deviation are calculated…
Q: The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.4 15 15.7 16…
A: Given data, 15.4, 15, 15.7, 16 , 15.4, 15.1 , 15.7, 15.3 From given data, sample mean is…
Q: Consider the following results for independent samples taken from two populations. Sample 1…
A: Confidence interval for the difference between the two population proportions is given by…
Q: A U.S. Food Survey showed that Americans routinely eat beef in their diet. Suppose that in a study…
A: Given, n1=49, x1=54.1, S1=7.0, n2=64, x2=60.4, S1=8.0…
Q: In a study of the accuracy of fast-food drive-through orders, a restaurant had 36 orders that were…
A:
Q: A market analyst is curious what proportion of Los Angeles residents have a landline telephone. A…
A: Given that, A survey of 200 randomly selected Los Angeles residents shows that 96 of those selected…
Q: In an articie in the Journal of Advertising, Weinberger and Spotts compare the use of humor in…
A:
Q: In a study of the accuracy of fast food drive-through orders, Restaurant A had 241 accurate orders…
A: It is given that Restaurant had 241 accurate orders and 71 are not accurate orders. The total number…
Q: 1. A recent survey showed that from a sample of 500 packages delivered by a Postal Service, 480 were…
A: We have given that Sample size n= 500 , favorable cases x=480 Sample proportion p^=x/n=…
Q: In a situation where the sample size was decreased from 39 to 29, what would be the impact on the…
A: The confidence interval depends on the three factors: Confidence level: The width of the…
Q: A recent survey of cell phone users indicated that 56 percent of the respondents prefer to use cell…
A: Given that 56% of the respondents prefer to use cell phones for texting rather than for making phone…
Q: he Pew Social Media Update 2014 surveyed 1,597 adult internet users on which social media websites…
A: Given information- We have given that Social Media Update 2014 surveyed 1,597 adult internet users…
Q: Researchers at the National Cancer Institute released the results of a study that examined the…
A: Given , (1-α)100% = 95% α = 0.05
Q: I would like to test the hypothesis that the average round trip airfare between Phoenix and San…
A: Given For phoenix Sample mean= x̄1=240, sample size=n1=18, sample standard deviations s1 =70 For…
Q: a) Using a sample size of 75, construct a 95% confidence interval estimate of the mean birth weight…
A: here given , A study has been conducted to verify the mean of birth weight at Apple County. From…
Q: How many subjects would be needed to ensure that a 95% confidence interval estimate of BMI had a…
A: Given data set is28,21,37,38,24,28,38,47,27,32,36,43sample size(n)=12confidence level=95%Margin of…
Q: The table below shows the number of car wrecks that occur during certain times of the day: Time 12 -…
A: Part (A) The 95% confidence interval for proportion of wrecks is given by the formula: Find the…
Q: The average total dollar purchase at a convenience store is less than that at a supermarket. Despite…
A: Solution-: Given: We find 90% C.I. for the population
Q: Two types of flares are tested and their burning times are recorded. The summary statistics are…
A: Note: Hey there! Thank you for posting the question. For the calculation we are considering x1 as…
Q: A sample of part time students are asked how many hours per week they work on a job. For the…
A: There are only 5 values in the sample data. Scores: 18 13 12 15 12
Q: In a recent poll, 19% of respondents answered option A. The margin of sampling error was plus or…
A: Given information- The percentage of the population answered A is, p = 19% The margin of error, E…
Q: A clinic offers a weight-loss program. A review of its records found the following amounts of weight…
A: Given data is appropriate for t-test because the sample size is less than 30. so, we need to go far…
Q: An airline transports over 10 000 passengers daily, and the airline is curious what proportion of…
A: Critical value: Using Excel formula "=NORM.S.INV(1-(0.1/2))", the z-value is obtained as 1.645.
Q: Data collected by a behavioral risk factor surveillance group revealed that in a state, 27.9% of…
A: Givena)Let p1 and p2 be the proportion of whites and blacks who were cigarette smokers…
Q: In order to determine if weather conditions play a significant role in how a disease effects wheat,…
A: Given:
Q: in a study of the accuracy of fast food drive thru orders, restaurant A had 209 accurate orders and…
A:
Q: What would be the standard error in computing a confidence interval for the difference of…
A: It is given that For population 1, sample size n1 = 49, sample proportion = 0.682 For population 2,…
Step by step
Solved in 2 steps with 2 images
- What is meant by the sample space of an experiment?In a situation where the sample size was decreased from 39 to 29 in a normally distributed data set, what would be the impact on the confidence interval?A research group studying cell phone habits asked the question “Do you ever use your cell phone to make a payment at a convenience store?” to people selected from two random samples of cell phone users. One sample consisted of older adults, ages 35 years and older, and the other sample consisted of younger adults, ages 18 years to 34 years. The proportion of people who answered yes in each sample was used to create a 95 percent confidence interval of (0.097,0.125)(0.097,0.125) to estimate the difference (younger minus older) between the population proportions of people who would answer yes to the question. Which of the following is the best description of what is meant by 95 percent confidence? In repeated random sampling with the same sample size, approximately 95% of the sample proportions from the younger group will be between 0.097 and 0.125 greater than the sample proportion from the older group. A In repeated random sampling with the same sample size,…
- In a situation where the sample size was decreased from 39 to 29, what would be the impact on the confidence interval?Suppose that a safety group surveyed 1,100 drivers. Among those surveyed, 65% said that careless or aggressive driving was the biggest threat on the road, and 25% said that cell phone usage by other drivers was the driving behavior that annoyed them the most. Based on these data and assuming that the sample was a simple random sample, construct and interpret a 95% confidence interval estimate for the true proportion in the population of all drivers who are annoyed by cell phone users. The confidence interval estimate is ??––––––??> (Round to three decimal places as needed. Use ascending order.) Interpret the confidence interval estimate. A. There is a 0.95 probability that the population proportion of drivers who are annoyed by cell phone users is in the interval. B. There is 95% confidence that the population proportion of drivers who are annoyed by cell phone users is in the interval. C. There is 95% confidence that the population proportion…An epidemiologist is worried about the prevalence of the flu in East Vancouver and the potential shortage of vaccines for the area. She will need to provide a recommendation for how to allocate the vaccines appropriately across the city. She takes a simple random sample of 339 people living in East Vancouver and finds that 40 have recently had the flu. For each of the following statements, specify whether the statement is a correct interpretation of the 95% confidence interval for the true proportion of East Vancouver residents who have recently had the flu. A. 11.80% (40/339) of East Vancouver residents have recently had the flu. ? true false B. There is a 95% probability that the true proportion of East Vancouver residents who have recently had the flu equals 40/339. ? true false C. If another random sample of 339 East Vancouver residents is drawn, there is a 95% probability that the sample proportion of East Vancouver residents who have recently had the flu equals 40/339. ?…
- In a study by Sallie Mae and Gallup, 323 of the 569respondents said that they paid for their education by taking out student loans. Find a 95% confidence interval for the proportion of students who paid for their education by taking out student loans.In a survey of 500 students, 180 students said that they prefer classes on Mondays and Wednesdays rather than on Tuesdays and Thursdays. Using a 95% confidence interval, answer the following questions. a. What is the margin of error for this study? b. Construct a 95% confidence interval that estimates the proportion of students that prefer classes on Mondays and Wednesdays.In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full-time college students who earn a bachelor's degree in four years or less. Find the sample size needed to estimate that percentage. Use a 0.03 margin of error and use a confidence level 90%.