int[] list = {-35,4,-50,2} and the length= 4 (binary search Algorithm) use the sorted list above and search for number 100, show the value of low, high, mid and the call. binarySearch(list, key, low, high);
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int[] list = {-35,4,-50,2} and the length= 4
(binary search
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- Write code to partition a linked list around a value x, such that all nodes less than x come before all nodes greater than or equal to x. If x is contained within the list, the values of x only need to be after the elements less than x (see below). The partition element x can appear anywhere in the "right partition"; it does not need to appear between the left and right partitions.EXAMPLEInput:Output:3 -> 5 -> 8 -> 5 -> 10 -> 2 -> 1 [partition= 5]3 -> 1 -> 2 -> 10 -> 5 -> 5 -> 8Create a java linked list that will perform adding,searching,removing, and changing element that will produce same output belowA singly linked list can perform insertion and deletion of nodes from both ends in constant time. True or False?
- Write code to partition a linked list around a value x, such that all nodes less than x comebefore all nodes greater than or equal to x. If x is contained within the list the values of x only needto be after the elements less than x (see below). The partition element x can appear anywhere in the"right partition"; it does not need to appear between the left and right partitions.EXAMPLEInput: 3 -> 5 -> 8 -> 5 -> 10 -> 2 -> 1 [partition= 5]Output: 3 -> 1 -> 2 -> 10 -> 5 -> 5 -> 8/ This method takes as parameters a reference to the head of a linked list, a // position specified by n, and a key. It returns the number of occurrences // of the key in the linked list beginning at the n-th node. If n = 0, it means // you should search in the entire linked list. If n = 1, then you should skip // the first node in the list. public int numOccurrencesRec(LNode node, int n, int key) { // TODO: implement this method return 0; // replace this statement with your own return } } LNode Below: public class LNode{ // instance variables private int m_info; private LNode m_link; // constructor public LNode(int info) { m_info = info; m_link = null; } // member methods public void setLink(LNode link) { m_link = link; } public LNode getLink() { return m_link; } public int getInfo() { return m_info; } }// This method takes as parameters a reference to the head of a linked list, a // position specified by n, and a key. It returns the number of occurrences // of the key in the linked list beginning at the n-th node. If n = 0, it means // you should search in the entire linked list. If n = 1, then you should skip // the first node in the list. public int numOccurrencesRec(LNode node, int n, int key) { // TODO: implement this method return 0; // replace this statement with your own return }}
- Write a Java program which stores three values by using singly linked list.- Node class1. stuID, stuName, stuScore, //data fields2. constructor3. update and accessor methods- Singly linked list class which must has following methods:1. head, tail, size// data fields2. constructor3. update and accessor methodsa. getSize() //Returns the number of elements in the list.b. isEmpty( ) //Returns true if the list is empty, and false otherwise.c. getFirstStuID( ), getStuName( ), getFirstStuScore( )d. addFirst(stuID, stuName, stuScore)e. addLast(stuID, stuName, stuScore)f. removeFirst ( ) //Removes and returns the first element of the list.g. displayList( ) //Displays all elements of the list by traversing the linked list.- Test class – initialize a singly linked list instance. Test all methods of singly linked list classYou have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.Input: (6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912You have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.EXAMPLElnput:(6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912
- Write a Java program which stores three values by using doubly linked list.- Node class4. stuID, stuName, stuScore, //data fields5. constructor6. update and accessor methods- Singly linked list class which must has following methods:4. head, tail, size// data fields5. constructor6. update and accessor methodsa. getSize() //Returns the number of elements in the list.b. isEmpty( ) //Returns true if the list is empty, and false otherwise.c. getFirstStuID( ), getStuName( ), getFirstStuScore( )d. addFirst (stuID, stuName, stuScore)e. addLast(stuID, stuName, stuScore)f. removeFirst( ) //Removes and returns the first element of the list.g. removeLast( ) //Removes and returns the first element of the list.h. displayList( ) //Displays all elements of the list by traversing the linked list.- Test class – initialize a doubly linked list instance. Test all methods of doubly linked list class.Which code part (A, B, C, or D) is incorrect? Add element in Linked List at particular index: add(int index, T item) void add(int index, int value) { // A. ============================================= if(index < 0 || index > count){ cerr << "Index Out of Bounds"; return; } node *temp = new node; temp->item = value; // A. ============================================= // B. ============================================= if (index == 0) { temp->next = head; head = temp; } // B. ============================================= // C. ============================================= else { node *previous = head; for(int i = 0; i < index - 1; ++i){ previous = previous->next; } // C. ============================================= // D. ============================================= previous->next = temp; temp->next = previous->next; } // D. ============================================= ++count; return; }implement this method: numOccurrencesRec(LNode node, int n, int key) – This method takes as parameters a reference to the head of a linked list, a position specified by n, and a key. It returns the number of occurrences of the key in the linked list beginning at the n-th node. If n = 0, it means you should search in the entire linked list. If n = 1, then you should skip the first node in the list.