Ionic and Net Ionic equations

A Ce4+ solution is standardized by titrating it with a 0.1952 M Sn2+ solution. The balanced net ionic equation for the reaction is:2Ce4+(aq)  +  Sn2+(aq)2Ce3+(aq)  +  Sn4+(aq)If 21.06 mL of the 0.1952 M Sn2+ solution is required to react completely with 40.00 mL of the Ce4+ solution, calculate the concentration of the Ce4+ solution.

AgNO3 (aq) + KI (aq) --> what is the net ionic equation?

Write net ionic equations for the following reactions:

Write a molecular, total ionic, and net ionic equation for the following reaction: 2NaOH (aq) + CuSO4(aq) -> Na2SO4 (aq) + Cu(OH)2 (s)

If 785 mL of 0.350 M AgNO₃ is added to 475 mL of 0.250 M CaBr₂, how many moles of AgBr precipitate will be formed? The balanced equation is 2 AgNO₃(aq) + CaBr₂(aq) → 2 AgBr(s) + Ca(NO₃)₂(aq)

Calculate the number of milliliters of 0.779 M KOH required to precipitate all of the Pb²* ions in 122 mL of 0.541 M Pb(NO3)2 solution as Pb(OH)2. The equation for the reaction is: Pb(NO3)2(aq) + 2KOH(aq) –→Pb(OH)2(s) + 2KNO3(aq) mL KOH

Pb(NO3)2(aq) +  2 KI(aq)     2 KNO3(aq)       + [   PbI2(s)   ] what is the - molecular equation - total ionic equation - net ionic equation

What is the net ionic equation for the following reaction? NazCO3(aq) + FeCI2(aq) --> FeCO3(s) + 2NaCl(aq)

Calculate the number of milliliters of 0.754 M KOH required to precipitate all of the Zn2+ ions in 162 mL of 0.731 M Zn(NO3)2 solution as Zn(OH)2. The equation for the reaction is: Zn(NO3)2(aq) + 2KOH(aq) Zn(OH)2(s) + 2KNO3(aq)