Java, Rewrite the following iterative method as a recursive method that computes the same thing.  Note:  your recursive method will require an extra parameter. public int iterative1(int x) { int count = 0, factor = 2; while (factor < x) { if (x % factor == 0) count++; factor++; } return count; }

Question 4 Consider the following recursive method. public static void mystery(int x) { if(x % 5 >= 2) { mystery(x + 1); } if(x % 5 1) { mystery(x - 1); } 11 System.out.print(x + "); } What is output by mystery (18) ? 19 20 20 19 == 20 19 18 17 20 19 18 20 1 pts

Write code in Java: -Must be recursive import java.util.*; import java.lang.*; import java.io.*; //*Analysis goes here*   //*Design goes here* class AllPermutation { public static void displayPermutation(String s) { //*Code goes here* } public static void displayPermutation(String s1, String s2) { //*Code goes here* } } //*Driver class should not be changed* class DriverMain { public static void main(String args[]) { Scanner input = new Scanner(System.in); AllPermutation.displayPermutation(input.nextLine()); } }

Using the code in the image provided: Implement a method called summation which adds two integers and returns their sum. INPUT: The first line of input contains an integer a. The Second Line of input containes and integer b. OUTPUT: Print the result which is the sum of a and b.

Do the trace in detail and submit  The source Code As Well From the following recursive method Trace (in details) the calling of the above method with any input from your choice such that thereturned value will be 19. public static int think(int x) {if(x<10)if(x%2!=0)return x;elsereturn 0;elseif(x%2!=0)return x%10 + think(x/10);elsereturn think(x/10);}

write a code in java (using recursion)

Java - Write an iterative method that calculates the SUM of all integers between 1 and a given integer N (input into the method). Write a corresponding recursive solution. (return answer, don’t print)

The following recursive method called z is created. This method accepts two parameters: A string s, and an integer index  The code in the method is:      if (index == s.length())        return "";          <------ base case     if(index % 2 == 0)        return ""+ s.charAt(index) + z(s,index+1);           <---- recursive call     else        return z(s,index+1);             <----- recursive call   What would be the output with the call:   z("javajavajava",0);

public class Main {    public static void main(String[] args) {        System.out.println("Your factorial is: " + factorial(9));    }} public static int factorial(int number) {        if (number == 0) {        return 1;    }        return number * factorial(number -1);    }   i need help fixing this code involving recursion

The factorial of a positive integer n —which we denote as n!—is the product of n and the factorial of n 1. The factorial of 0 is 1. Write two different recursive methods in Java that each return the factorial of n. Analyze your algorithm in Big-Oh notation and provide the appropriate analysis, ensuring that your program has a test class.