gent pleaseQ1):a writeaplograme that take Values intwo integet aays A and B of Size 5.b): stove thethindc): Pintt Maked) Makegain Rrint elementsorder.sumof att ay A and B inthointeger Mayc of Sıze 5arrays cdhreh c*elements o f arla c odd, andofelementsofPtogramevenall ay C inYevriseTh

cout<< "Enter 5 element for array A: "; for(int i=0;i<5;i++) { cin >> a[i];…

Lngent please Q1): a) write a programe that take Values in two Tnteger alay s A and B of size 5 b): stove the thind c): Puint t Make Sum of att ay A and B intho integer aMay cof size 5 arlays C dHven c* Progtam elements of menu

Lngent please Q1): a) write a programe that take Values in two Tnteger alay s A and B of size 5 b): stove the thind c): Puint t Make Sum of att ay A and B intho integer aMay cof size 5 arlays C dHven c* Progtam elements of menu

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

#ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…
#include<stdio.h> #include<iostream>using namespace std; int main() { int arr [7] = {9, 4, 1, 6, 2}; int i, j, k, temp, n=5; for(i=0;i<n-1;i++){ for (j = i+1; j<n; j++){ if (arr[i]>arr[j]){ //swap the elements temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } cout<<"The sorted array is: "; for (k=0; k<n;k++) { cout<<arr[k]<<' '; } } Question: Rewrite the Program using function.
Vectors Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid vector element, such as courseGrades.at(9) for a 4-element vector, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> courseGrades(NUM_VALS);int i; for (i = 0;…
def create_identity_matrix(n):"""Create a nxn sized identity matrix. The return type should be a list or numpy ndarrayFor more info: https://en.wikipedia.org/wiki/Identity_matrixFor this exercise you can use nested loops to construct your 2d array or find an applicable function in the numpy library.:param n::return: nxn ndarray where the diagonal elements are 1 and nondiagonal elements are 0"""pass
Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList = {40, 50, 60, 70} and offsetAmount = {5, 7, 3, 0}, print: 45 57 63 70 #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> origList(NUM_VALS);vector<int> offsetAmount(NUM_VALS);unsigned int i; for (i = 0; i < origList.size(); ++i) {cin >> origList.at(i);} for (i = 0; i < offsetAmount.size(); ++i) {cin >> offsetAmount.at(i);} cout << endl; return 0;} Please help me with this problem using c++.
Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >> courseGrades.at(i); }…
Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >> courseGrades.at(i);…
Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes…
T/F Suffix array can be created in O(nlogn) time.
it Language Java 8 Autocomplete Ready O 3. Closest Numbers 1 > import java.io.*; - 14 15 class Result { 16 Given an array of distinct integers, determine the minimum absolute difference between any two elements. Print all element pairs with that minimal absolute difference in ascending order. * Example numbers = [6,2,4,10] The minimal absolute difference is 2 and the pairs with that difference are (2,4) and (4,6). When printing element pairs (1) they should be ordered ascending first by i and then by j. 17 /* 18 * Complete the closest Numbers' function below. 19 20 * The function accepts INTEGER_ARRAY numbers as parameter. 21 */ 22 23 public static void closestNumbers (List numbers) { 24 // Write your code here 25 26 } 27 28 } 29 30 > public class Solution { 2 4 4 6 Function Description Complete the function closestNumbers in the editor below. closestNumbers has the following parameter(s): int numbers[n: an array of integers Returns: NONE Line: 14 Co Test Results Custom Input Run…
TODO 1: To construct an array of 120 values between -4 and 4, use the NumPy method np.linspace() (docs). To do so, pass the parameters -4, 4, and 120. Put the results in the variable x_values. mu = 0 # mean sig = 1 # std # TODO 1 x_values = display(x_values) todo_check([ (x_values.shape == (120,),'x_values does not have the correct shape of (120,)'), (np.all(np.isclose(x_values, np.array([-4.…
complete the //TODOs #include<iostream> #include "swap.h" using namespace std; int main(int argc, char const *argv[]) { intfoo[5] = {1, 2, 3, 4, 5}; cout<<"Addresses of elements:"<<endl; //TODO Print the addresses of array elements cout<<endl; cout<<"Elements:"<<endl;; //TODO Print all the elements using pointers cout<<endl; inta,b; intf; intflag = 1; while(flag == 1){ cout<<"Enter indices of elements you want to swap?"<<endl; cout<<"First index"<<endl; cin>>a; cout<<"Second index"<<endl; cin>>b; cout<<"Enter 0 for pass-by-value, 1 for pass-by-pointer"<<endl; cin>>f; switch (f) { case0: // Pass by Value // Compare the resultant array with the array you get after passing by pointer cout<<"Before swapping"<<endl; for(inti = 0;i<5;i++){ cout<<foo[i]<<" "; } cout<<endl; swap(foo[a],foo[b]); cout<<"\nAfter swapping"<<endl;…