Min Stack (interesting stack implementation): Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. Implement the MinStack class: MinStack() initializes the stack object. void push(int val) pushes the element val onto the stack. void pop() removes the element on the top of the stack. int top() gets the top element of the stack. int getMin() retrieves the minimum element in the stack. You must implement a solution with O(1) time complexity for each function. Code in Java. A brief explanation of how and why your code works and how it relates to the concepts learned (for example, it uses bitwise operation, stack, or takes into account a word size).

solution for subpart 4

0:00 I ZVV 58 Stack s - new Stack(); s. push(10); s. push(20); s. push(30); s. push(40); // stack created with elements- 10 20 30 40 59 60 61 62 63 64 65 sum(s); 66 public static void sum(stack s){ Integer sum = 0; stack tmp = new Stack(); // move the stack to new stack, it will be in reverse orde // simultaneously sum the elements while (Is.isEmpty())( tmp.push(s.pop(); sum t tmp.peek(); 67 68 69 70 71 72 73 74 sum t= tmp.peek (); 74 75 // move to original stack while (Itmp.isEmpty()){ s.push(tmp.pop()); system.out.println("sum= "+sum.tostring()); OUTPUT- 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack 40 pushed into stack 30 pushed into stack 20 pushed into stack 10 pushed into stack 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack Sum= 100 Sum of 10, 2O, 30, 40 = 100 I hope it helps. For any doubt, feel free to ask in comments, and give upvote if u get the answer.

How much does the stack work best when it's allowed to do what it naturally wants to do?