In the temperature range 0-90 ºC , the potential difference of the following cell: Pt (s) | H2 (g, f = 1) | HCl (aq, m = 0.1) | AgCl (s) | Ag (s) changes as follows with the temperature: Ecell (V) = 0.35510 – 0.3422x10-4t - 3.2347x10-8t2 + 6.314x10-9t3 (t being the temperature in ºC) Write the reaction and calculate ΔG, ΔH and ΔS at 90 ºC. In the temperature range 0-90 °C , the potential difference of the following cell:Pt (s) | H2 (g,ƒ= 1)| HCI (aq, m = 0.1)| AgCl (s) | Ag (s)manges as follows with the temperature:Epila (V) = 0.35510 – 0.3422x10-4t - 3.2347x10-8f2 + 6.314x10-f³ (t being the temperature°C)rite the reaction and calculate AG, AH and AS at 90 °C.

The equation that describes the relationship between Gibbs free energy ∆G and emf of cell Ecell is…

Answered: n the temperature range 0-90 ºC , the…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter19: Applications Of Standard Electrode Potentials

Section: Chapter Questions

Problem 19.8QAP

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In the temperature range 0-90 ºC , the potential difference of the following cell:
Pt (s) | H₂ (g, f = 1) | HCl (aq, m = 0.1) | AgCl (s) | Ag (s)
changes as follows with the temperature:
Ecell (V) = 0.35510 – 0.3422x10^-4t - 3.2347x10^-8t² + 6.314x10^-9t³ (t being the temperature in ºC)
Write the reaction and calculate ΔG, ΔH and ΔS at 90 ºC.

In the temperature range 0-90 °C , the potential difference of the following cell:
Pt (s) | H2 (g,ƒ= 1)| HCI (aq, m = 0.1)| AgCl (s) | Ag (s)
manges as follows with the temperature:
Epila (V) = 0.35510 – 0.3422x10-4t - 3.2347x10-8f2 + 6.314x10-f³ (t being the temperature
°C)
rite the reaction and calculate AG, AH and AS at 90 °C.

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