Use the isotope method to determine the molecular formula СНEM 3132NMR IR MS Homework OneMass Spectrum Datam/erelative abundance1347.20.711351360.05Moiecular Formula Data for Mass 134М+1 М+25.72 0.94CSH10O4CH14036.83 0.808.82 0.74CH1009.93 0.6411.03 0.55100 -5-N-S1380-60-4020-20406080100120140160180200m/zRelative htensity

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Answered: NMR Mass Spectrum Data m/e relative…

NMR Mass Spectrum Data m/e relative abundance 134 7.2 0.71 0.05 135 136 Moiecular Formula Data for Mass 134 M+1 M+2 5.72 0.94 6.83 0.80 CH14O3 CHO2 CH100 C1H14 8.82 0.74 9.93 0.64 11,03 0,55

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter10: Atomic Emission Spectrometry

Section: Chapter Questions

Problem 10.11QAP

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Atoms and Molecules

An atom is the smallest unit of an element that possesses all the properties of that particular element. Molecules are the smallest unit of a substance that possess all the properties of that particular substance.

Question

Use the isotope method to determine the molecular formula

СНEM 3132
NMR IR MS Homework One
Mass Spectrum Data
m/e
relative abundance
134
7.2
0.71
135
136
0.05
Moiecular Formula Data for Mass 134
М+1 М+2
5.72 0.94
CSH10O4
CH1403
6.83 0.80
8.82 0.74
CH100
9.93 0.64
11.03 0.55
100 -
5-N-S13
80-
60-
40
20-
20
40
60
80
100
120
140
160
180
200
m/z
Relative htensity

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