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nRT -)dv nR dX = ( -) dT (- V where R (= 0.08206 atm-L/mol-K or 8.314 J/mol-K) is the gas constant; n is the number of mole, V is the volume and T is the temperature. av Determine the value of (in units of L (liter) and K (Kelvin)) when n = 4.00 mol, V = 114.8L and T = 350 K (with 3 significant figures).

nRT -)dv nR dX = ( -) dT (- V where R (= 0.08206 atm-L/mol-K or 8.314 J/mol-K) is the gas constant; n is the number of mole, V is the volume and T is the temperature. av Determine the value of (in units of L (liter) and K (Kelvin)) when n = 4.00 mol, V = 114.8L and T = 350 K (with 3 significant figures).

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter5: Gases, Liquids, And Solids
Section: Chapter Questions
Problem 5.26P
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nR dT nRT -)dv dX where R (= 0.08206 atm-L/mol-K or 8.314 J/mol-K) is the gas constant; n is the number of mole, V is the volume and T is the temperature. av Determine the value of (in units of L (liter) and K (Kelvin)) when n = 4.00 mol, V = 114.8L and T = 350 K (with 3 significant figures). %3D
Transcribed Image Text:nR dT nRT -)dv dX where R (= 0.08206 atm-L/mol-K or 8.314 J/mol-K) is the gas constant; n is the number of mole, V is the volume and T is the temperature. av Determine the value of (in units of L (liter) and K (Kelvin)) when n = 4.00 mol, V = 114.8L and T = 350 K (with 3 significant figures). %3D
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