num1 = int(input("Enter first value:")) num2 = int(input("Enter second value:")) num3 = int(input("Enter third value:")) # Type your code after this line. if (num1 >= num2) and (num1 >= num3): print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num1 ) elif (num2 >= num1) and (num2 >= num3): print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num2 ) elif (num3 >= num1) and (num3 >= num2): print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num3 )

java

def f(x: float) -> int: return int(x) def g(x: str) -> float: return float(x) y = f(g("3.14")) Select all of the following statements that are true: y's inferred data type is float O y 's inferred data type is str O y's inferred data type is int There is a type error in this program None of the above are true

Complete the following Code

Function Name: compliments Parameters: answer1 - a boolean (True or False) representing whether the user is "smart" answer2 - a boolean (True or False) representing whether the user is "awesome" answer3 - a boolean (True or False) representing whether the user is "fun" Description: Write a function that outputs a string of compliments based on the adjectives selected by the inputs. Use the inputs True and False. The function should return the string “You are” concatenated with the compliments that are true. The three compliments should be: "smart" "awesome" and "fun". If none of the compliments are true, print the string “Goodbye.” instead. Test Cases: >>>compliments(True, True, True) You are smart awesome fun. >>>compliments(False, True, False) You are awesome. >>>compliments(False, False, False) Goodbye.

int input;        cout << "enter input " << endl;        cin >> input;        int i = input / 2;        int d;        for (i >= 2; i--;) {               d = input % i;               if (d == 2 || i == 1)                      cout << "not prime" << endl;               else                      cout << "prime" << endl; } This code outputs prime numbers as both "prime" and "not prime" but I just want it to say "prime". Please help me with this problem using c++.

#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…

python please explain

my_round(number, integer): Based on the built-in round(...) function. Takes an integer or float and returns a rounded float value that is the number rounded to the second argument's decimal place. First argument can be any float or integer. Second argument must be an integer. Examples: my_round(1234.5678, 2) and round(1234.5678, 2) should return 1234.57. my_round(1234.5678, -2) and round(1234.5678, -2) should return 1200.0.

int main(){    string str;    int count = 0;    // user input    cout << "Enter string: ";    cin >> str;    int n = str.length();    // iterating over the string    for (int i = 0; i < n - 1; i++)    {        // calling the fucntion to find the palidrome strings from the user input        if (isPalindrome(0, i, str) && isPalindrome(i + 1, n - 1, str))        {            // if 2 substring are palindrome then print them and increment count            for (int x = 0; x < i + 1; x++)                cout << str[x];            cout << " ";            for (int x = i + 1; x < n; x++)                cout << str[x];            count++;            // break the loop after printing the palindrom string            break;        }    }    // if count is 0 then no palindrome subtring pair found    if (count == 0)        cout << "NO";} change this code to stdio.h string.h