of the C-terminal domian of Pol Lack of phosporylation Il will result in which of the following? O Assembly of the full set of general transcription factors plus Pol II at the promoter, but unphosphorylated Pol II cannot leave the promoter region No assembly of the general transcription factors at a promoter No binding of Pol II at a promoter The unphosphorylated Pol II can initiate and elongate but cannot terminate

of the C-terminal domian of Pol Lack of phosporylation Il will result in which of the following? O Assembly of the full set of general transcription factors plus Pol II at the promoter, but unphosphorylated Pol II cannot leave the promoter region No assembly of the general transcription factors at a promoter No binding of Pol II at a promoter The unphosphorylated Pol II can initiate and elongate but cannot terminate

Name: Lack of phosporylation of the C-terminal domian of PolIl will result
Uploaded: 2024-03-20T06:42:55.000Z
Channel: Bartleby
Description: Lack of phosporylation of the C-terminal domian of PolIl will result in which of the following?O Assembly of the full set of general transcription factors plusPol II at the promoter, but unphosphorylated Pol II cannotleave the promoter regionNo asse

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section: Chapter Questions

Problem 21QP: Transcriptional regulators are proteins that bind to promoters (the 5-flanking regions of genes) to...

See similar textbooks

Similar questions

You have isolated a protein that binds to DNA in theregion upstream of the promoter sequence of the sysgene. If this protein is a positive regulator, which ofthe following would be true?a. Loss-of-function mutations in the gene encodingthe DNA-binding protein would cause constitutiveexpression of sys.b. Loss-of-function mutations in the gene encodingthe DNA-binding protein would result in little orno expression of sys.
Mutations in bacterial promoters may increase or decrease therate of gene transcription. Promoter mutations that increasetranscription are termed up-promoter mutations, and those thatdecrease transcription are termed down-promoter mutations.The sequence of the −10 site of the promoter for the lac operonis TATGTT (see Figure 14.5). Would you expect each of thefollowing mutations to be an up-promoter or down-promotermutation?A. TATGTT to TATATTB. TATGTT to TTTGTTC. TATGTT to TATGAT
Some transcription regulators bind to DNA andcause the double helix to bend at a sharp angle. Such“bending proteins” can affect the initiation of transcrip-tion without directly contacting any other protein. Can youdevise a plausible explanation for how such proteins mightwork to modulate transcription? Draw a diagram that illus-trates your explanation.
Consider a mutation in -10 BOX promoter consensus sequence (TATAAT) in the prokaryote recA gene where the first T base mutated to G, what outcome(s) are likely? a. transcription levels will increase as the GC content would increase b. this mutation is silent, so no change in transcription level c. transcription levels would decrease because the promoter would be weaker d. transcription levels do not depend on the promoter sequence for the gal gene e. nothing would happen because the promoter would not change the mRNA sequence
Mechanisms that inhibit TE activity include theproduction of transposition repressors throughalternative splicing and the action of _________ thatblock TE transcription.
. An interesting mutation in lacI results in repressorswith 110-fold increased binding to both operator andnonoperator DNA. These repressors display a “reverse”induction curve, allowing β-galactosidase synthesis inthe absence of an inducer (IPTG) but partly repressingβ-galactosidase expression in the presence of IPTG. Howcan you explain this? (Note that, when IPTG binds a repressor, it does not completely destroy operator affinity,but rather it reduces affinity 110-fold. Additionally, ascells divide and new operators are generated by thesynthesis of daughter strands, the repressor must findthe new operators by searching along the DNA, rapidlybinding to nonoperator sequences and dissociating fromthem.)
a. Very few if any eukaryotic genes contain tractswith more than 25 As or Ts in a row, yet almost alleukaryotic mRNAs have a tract with more than100 As in a row. How is this possible?b. Scientists know the nucleotide sequences that directthe termination of bacterial gene transcription, butthey generally have little idea about the nature ofthe nucleotide sequences that direct transcriptiontermination in eukaryotic cells. Explain the basisof this statement.
. In an effort to determine the location of an operator sitefor a negatively regulated gene, you have made a seriesof deletions within the regulatory region. The extent ofeach deletion is shown by the line underneath the sequence, and the resulting expression from the operon(i = inducible; c = constitutive; − = no expression) isalso indicated.... GGAT C T T AGCCGGCTAACATGATAAATATAA......C C T AGAATCGGCCGA TTGTA C T A TTT ATAT T ...1 i2 –3 c4 –5 ca. What can you conclude from these data about thelocation of the operator site?b. Why do you think deletions 2 and 4 show no expression of the gene?
Which of the following parts of the eukaryotic promoter are bound by general transcription factors? Group of answer choices A promoter proximal elements B enhancer elements C specific promoter elements D the core promoter E the distal promoter
Suppose that a new mutation lacIes, ('es' stands for ‘extra-strength’) has been discovered in the lac operon that allows the lac-repressor to bind even to the lacOc operator. Other properties of lacIes repressor remain normal (that is the same as of lacI+). Given this genotype Is P+ Oc Z+ Y- / Ies P+ O+ Z+ Y+ , under which conditions will the gene lacZ be transcribed to produce β-galactosidase and the gene lacY transcribed to produce permease? A) With lactose, β-galactosidase and permease are produced, without lactose they are not produced B) With lactose, β-galactosidase is produced, without lactose it is not; permease is never produced C) β-galactosidase is always produced and permease is never produced D) With lactose, β-galactosidase and permease are produced, without lactose they are also produced E) β-galactosidase is always produced and permease is produced only in the presence of lactose
The hunchback gene contains a 5′ transcriptional regulatory region, a 5′ UTR, a structural region (the coding sequences), and a 3′ UTR.a. What important sequences required to controlhunchback gene expression are found in the transcriptional regulatory region of hunchback?b. What sequence elements that encode specific protein domains are found in the structural region ofhunchback?c. Another important kind of sequence is located inthe 3′ UTR of the hunchback mRNA. What mightthis sequence do?
There are similarities and differences during regulation of gene expression in both prokaryotes and eukaryotes. Promoters, transcription factors and RNA polymerase are essential elements in transcription but their properties and function may differ.a) Predict the outcome or consequences of mRNA transcription by RNA polymerase II in eukaryote without the presence of transcription factors (TF).