Part CWhat is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.10 x 1015HZ ?Express your answer in joules to three significant figures.• View Available Hint(s)Ην ΑΣφ?X•10"KE=JSubmitPrevious Answers I RevElectrons are emitted from the surface of a metal when it's exposed tolight. This is called the photoelectric effect. Each metal has a certainthreshold frequency of light, below which nothing happens. Right atthis threshold frequency, an electron is emitted. Above this frequency,the electron is emitted and the extra energy is transferred to theelectron.Here are some data collected on a sample of cesium exposed to various energies of light.Light energy(eV)Electron KE(eV)Electron emitted?3.87noThe equation for this phenomenon is3.88noKE= hv – hvo3.89yeswhere KEis the kinetic energy of the emitted electron,h = 6.63 x 10 34 J.s is Planck's constant, v is the frequency of the3.90yes0.01light, and vy is the threshold frequency of the metal.3.91yes0.02*Note that 1 eV (electron volt) =1.60 × 10 1º J.Also, since E = hv, the equation can also be written asKE=E-6Part Awhere E is the energy of the light and ø is the binding energy of theelectron in the metal.

Kinetic energy of cesium E = hv Where h = plank's constant = 6.626 ×10-34 J s v = frequency of…

Part C What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.10 x 1015HZ ? Express your answer in joules to three significant figures. • View Available Hint(s) Ην ΑΣφ ? x" X IXI X•10" КЕ- J Submit Previous Answers

Part C What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.10 x 1015HZ ? Express your answer in joules to three significant figures. • View Available Hint(s) Ην ΑΣφ ? x" X IXI X•10" КЕ- J Submit Previous Answers

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter6: Electronic Structure And The Periodic Table

Section: Chapter Questions

Problem 80QAP: In the photoelectric effect, electrons are ejected from a metal surface when light strikes it. A...

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(a) Give the complete electron configuration (1s22s22p) of aluminum in the ground state. (b) The wavelength of the radiation emitted when the outermost electron of aluminum falls from the 4s state to the ground state is about 395 nm. Calculate the energy separation (in joules) between these two states in the Al atom. (c) When the outermost electron in aluminum falls from the 3d state to the ground state, the radiation emitted has a wavelength of about 310 nm. Draw an energylevel diagram of the states and transitions discussed here and in (b). Calculate the separation (in joules) between the 3d and 4s states in aluminum. Indicate clearly which has higher energy.
In the photoelectric effect, electrons are ejected from a metal surface when light strikes it. A certain minimum energy, Emin, is required to eject an electron. Any energy absorbed beyond that minimum gives kinetic energy to the electron. It is found that when light at a wavelength of 540 nm falls on a cesium surface, an electron is ejected with a kinetic energy of 2.601020J. When the wavelength is 400 nm, the kinetic energy is 1.541019J. (a) Calculate Emin for cesium in joules. (b) Calculate the longest wavelength, in nanometers, that will eject electrons from cesium.
Planck originated the idea that energies can be quantized. What does the term quantized mean? What was Planck trying to explain when he was led to the concept of quantization of energy? Give the formula he arrived at and explain each of the terms in the formula.
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6.29 A mercury atom emits light at many wavelengths, two of which are at 435.8 and 546.1 nm. Both of these transitions are to the same final state. (a) What is the energy difference between the two states for each transition? (b) lf a transition between the two higher energy states could be observed, what would be the frequency of the light?
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