Post-lab Question #2: How many grams of KMNO4 are required to prepare 2.000 L of 0.0300 M KMNO4 solution that is used in titrating Na2C204? 12.2 O 9.48 O 4.74 19.0
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- A 10.231-g sample of window cleaner containing ammonia was diluted with 39.466 g of water. Then 4.373 g of solution were titrated with 14.22 mL of 0.106 3 M HCl to reach a bromocresol green end point. (a) What fraction of the 10.231-g sample of window cleaner is contained in the 4.373 g that were analyzed? (b) How many grams of NH3 (FM 17.031) were in the 4.373-g sample? (c) Find the weight percent of NH3 in the cleaner.If a 0.750 g sample of protein-rich flour was subjected to a Kjeldahl analysis. Then the ammonia formed after digestion was distilled into 30.00 mL of 0.0500 M HCl, and the excess HCl was back titrated with 6.50 mL of 0.0400 M NaOH. Solve for both the percent N and percent protein (factor = 5.70) found in the flour.Assume that the molarity of the standardized KMnO4 solution is 0.025 M and it takes 23.00 mL to reach the endpoint when titrating a dilute sample of H2O2. How many moles of H2O2 are in the diluted sample initially? Group of answer choices
- student performed three KHP titrations in Part 1 in order to standardize their NaOH solution. They reported the following measurements: Determination #1 Determination #2 Determination #3 Mass of KHP + Vial 14.0862 g 14.5621 g 14.3998 g Mass of 'Empty' Vial 13.2492 g 13.7695 g 13.6887 g Final Burette Reading 45.10 mL 38.53 mL 37.17 mL Initial Burette Reading 5.08 mL 0.52 mL 3.19 mL Which determinations were the student's 'best two'? Calculate the percent difference for the 'best two' and show the complete calculation. with the right significant digitStandard oxylate solution used to standardize KMnO4 was prepared by dissolving 3.299g of Na2C2O4 in 1.000L of water containing H2SO4. add 25mL aliquot of the Na2C2O4 solution required 28.39 mL of KMnO4 for titration. A blank titration of 25mL of water containing H2SO4 required 0.03 mL of KMnO4. what is the molarity of the KMnO4 solution? 5C2O42-+2MnO4-+16H+ → 10CO2+2Mn2++8H2OA 20-tablet sample of soluble saccharin was treated with 20.00 mL of 0.08181 N AgNO3. After removal of the solid, titration of the filtrate and washings required 2.81 mL of 0.04124 N KSCN. Calculate the average number of milligrams of saccharin (205.17 g/mol) in each tablet.
- The benzoic acid extracted from 105.6 g of catsup required a 14.67 mL titration with 0.0514 N NaOH. Express the results of this analysis in terms of percent sodium benzoate. MW=144.10 g/mol Answer: % Na benzoate = Blank 1%(a) Standard oxalate was made by dissolving 3.514 g of Na2C2O4 in 1.000 L of 1 M H2SO4. A 25.00-mL aliquot required 24.44 mL of KMnO4 for titration, and a blank required 0.03 mL of KMnO4. Find the molarity of KMnO4. (b) To standardize NaNO2, 25.00 mL of KMnO4 solution from part (a) of this problem required 38.11 mL of NaNO2. Find the molarity of the NaNO2.What is the cobalt(II) ion concentration in a solution prepared by mixing 357 mL357 mL of 0.396 M0.396 M cobalt(II) nitrate with 475 mL475 mL of 0.399 M0.399 M sodium hydroxide? The ?spKsp of cobalt(II) hydroxide is 5.92×10−155.92×10−15 .
- You were assigned to assay a product sample of milk of magnesia. A 0.600-g sample was reacted with 25.00 mL 0.10590 N H2SO4 . The excess unreacted acid in the solution required 13.00 mL of 0.09500 N NaOH when titrated to reach the methyl red end point. Determine the dosage strength of the product in terms of % Mg(OH)2 content. Type your answer in 2 decimal places, numbers only.A student weighs out 0.9854 g of Na2CO3 unknown and dissolves it in 25.00 mL of deionized water. A 0.1934 M HCl solution is used as the titrant, and 25.98 mL is required to reach the final equivalence point (from methyl orange). What is the %Na2CO3 in the unknown? (Formula weights: HCl, 36.46 g/m; Na2CO3, 105.99 g/m)You are to make 300mL of 20mM EDTA buffer (C10H16N2O8) solution from powder. How much EDTA powder must be dissolved in water? [Atomic Weight: C = 12.011; H = 1.0079; O = 15.999; N = 14.0067]