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Pretend you have 267 g of each of the following substances is initially at 21.6 °C. What is the final temperature of each of these substance after they absorb 0.735 kJ of heat? Use the data in Table 6.4 from the textbook.

Pretend you have 267 g of each of the following substances is initially at 21.6 °C. What is the final temperature of each of these substance after they absorb 0.735 kJ of heat? Use the data in Table 6.4 from the textbook.

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter10: Energy
Section: Chapter Questions
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Pretend you have 267 g of each of the following substances is initially at 21.6°C. What is the final temperature of each of these substance after they absorb 0.735 kJ of heat? Use the data in Table 6.4 from the textbook.
Transcribed Image Text:Pretend you have 267 g of each of the following substances is initially at 21.6°C. What is the final temperature of each of these substance after they absorb 0.735 kJ of heat? Use the data in Table 6.4 from the textbook.
Since the volume area of its base times its Ax AA is actually the change in the volume (AV) that occurs during the ex- pansion. Thus, the expression for work AV is the final volume minus the initial volume, V-V, or V-V1. so during an expansion AV is positive and the work is negative, in agreement with the con- vention that if the system (the expanding gases) does work on the surroundings, its sign is negative. Volume change Choes sectional Intial etate Final state A RIGURE 6.6 Piston Moving Within a Cylinder Against an External Pressure EXAMPLE 6.4 PRESSURE-VOLUME WORK ae a haon, you must do pressure-volume work on the surroundings, If vou inflate a balloon from a volume of 0.100 L to 1.85 L against an external pressure of 1.00 bar, how much work is done (in joules)? SORT You know the initial and final volumes of the balloon and the pressure against which it expands. The halloon and its contents are the system. GIVEN: V = 0.100 L, V, = 1.85 L, P = 1.00 bar %3D FIND: w STRATEGIZE The equation w -PAV specifies the CONCEPTUAL PLAN amount of work done during a volume change against an external pressure. P, AV SOLVE To solve the problem, compute the value of SOLUTION AV and substitute it, together with P, into the equation. %3D = 1.85 L – 0.100 L = 1.75 L w = -PAV Convert the units of the answer (bar L) to J using 100 J 1 bar L. = -1.00 bar X 1.75 L f 00 1 bar L 3 -1.75 barL X CHECK The unit J is correct for work. The sign of the work is negative, as it should be for an expansion: Work is done on the surroundings by the expanding balloon. = -175 J FOR PRACTICE 6.4 When fuel is burned in a cylinder equipped with a piston, the volume expands from 0.255 L to 1.45L against an extern pressure of 1.02 bar. In addition, 875 J is emitted as heat. What is AU for the burning of the fuel?
Transcribed Image Text:Since the volume area of its base times its Ax AA is actually the change in the volume (AV) that occurs during the ex- pansion. Thus, the expression for work AV is the final volume minus the initial volume, V-V, or V-V1. so during an expansion AV is positive and the work is negative, in agreement with the con- vention that if the system (the expanding gases) does work on the surroundings, its sign is negative. Volume change Choes sectional Intial etate Final state A RIGURE 6.6 Piston Moving Within a Cylinder Against an External Pressure EXAMPLE 6.4 PRESSURE-VOLUME WORK ae a haon, you must do pressure-volume work on the surroundings, If vou inflate a balloon from a volume of 0.100 L to 1.85 L against an external pressure of 1.00 bar, how much work is done (in joules)? SORT You know the initial and final volumes of the balloon and the pressure against which it expands. The halloon and its contents are the system. GIVEN: V = 0.100 L, V, = 1.85 L, P = 1.00 bar %3D FIND: w STRATEGIZE The equation w -PAV specifies the CONCEPTUAL PLAN amount of work done during a volume change against an external pressure. P, AV SOLVE To solve the problem, compute the value of SOLUTION AV and substitute it, together with P, into the equation. %3D = 1.85 L – 0.100 L = 1.75 L w = -PAV Convert the units of the answer (bar L) to J using 100 J 1 bar L. = -1.00 bar X 1.75 L f 00 1 bar L 3 -1.75 barL X CHECK The unit J is correct for work. The sign of the work is negative, as it should be for an expansion: Work is done on the surroundings by the expanding balloon. = -175 J FOR PRACTICE 6.4 When fuel is burned in a cylinder equipped with a piston, the volume expands from 0.255 L to 1.45L against an extern pressure of 1.02 bar. In addition, 875 J is emitted as heat. What is AU for the burning of the fuel?
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