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- As a newly appointed research officer, Marissa has been assigned a task to separate a mixture containing acetone, acetamide and 1,2-dichloroethane using a high-performance liquid chromatography (HPLC) technique. The instrument was equipped with a 40-cm column packed with cyano propyl bonded to the siloxane backbone material. i) List THREE (3) examples of mobile phase solvent/solvent systems that can be used with the column above. ii) Determine the sequence in which the three analytes eluted from the column and explain the underlying principle applied. iii) Sketch the chromatogram that would be produced if the column was replaced with a column filled with C18 hydrocarbon bound to the siloxane backbone material and acetonitrile was employed as the mobile phase. Label the peaks observed.Internal standard. When 1.06 mmol of 1-pentanol and 1.53 mmol of 1- exanol were separated by gas chromatography, they gave relative peak areas of 922 and 1 570 units, respectively. When 0.57 mmol of pentanol was added to anunknown containing hexanol, the relative chromatographic peak areas were 843:816 (pentanol:hexanol). How much hexanol did the unknown contain?The following data give the recovery of bromide from spiked samples of vegetable matter, measuredusing a gas–liquid chromatographic method. The same amount of bromide was added to each specimen(Roughan, J.A., Roughan, P.A. and Wilkins, J.P.G., 1983, Analyst, 108: 742).Tomato: 777 790 759 790 770 758 764 ug/gCucumber: 782 773 778 765 789 797 782 ug/g(a) Test whether the recoveries from the two vegetables have variances which differ significantly.(b) Test whether the mean recovery rates differ significantly.
- (i) Calculate the capacity factors (k') for both compounds A and B and the selectivity factor (a) between them, commenting on the values. (ii) Calculate the resolution between A and B and comment on it. (iii) Using the peak for A, calculate the number of theoretical plates for the GC column and comment on the quality of the column.Thomas obtained a chromatogram for hydrocarbon analysis as below. He anticipated thathis setting may not be appropriate. Name the technique that he can use to optimize analyteseparation. Explain how would this technique help to improve his chromatogram.Gravimetric factor:A 1.0125 g portion of the sample was oven-dried leaving 0.9385 g of dry matter. In a similar experiment a 2.0163 g portion of the sample was oven-dried and extracted with a non-polar solvent. the solvent was evaporated leaving a 0.8444 g residue. what is the amount of crude fat present in the feed? (in %w/w, dry matter basis)
- For Indirect Iodometric Analysis of Copper... ~0.0896g KIO3 necessary to consume 350mL of 0.1 M Na2S2O3, Na2S2O3 is stored in an amber glass bottle until ready for use. Primary Standard KIO3 has 2g of KI, 50mL of DI water, and 10 mL of 1.0M HCl is added then immediately titrated with Na2S2O3 until medium yellow or straw... then 5mL of starch indicator is added and titrated again until blue black color turns clear. Unknown CuO use 1.2G of Unknown, 20mL of HNO3 heated until sample dissolved, 25 mL of DI water added and boiled until clear light blue color, after cooling 1:1 NH3 added (~34.47 mL of NH4OH reagent) until permanent deep blue color amine complex, 2g of NH4HF2 added and swirled until dissolved, 3 g of KI is added then titrated immediately with Na2S2O3 until brown color of iodide is nearly gone (brown milk color), 2 g of KSCN and 3 mL of starch indicator is then added with titration continuing until disappearance of new blue black color. 1. Na2CO3 is often added to thiosulfate…For Indirect Iodometric Analysis of Copper... ~0.0896g KIO3 necessary to consume 350mL of 0.1 M Na2S2O3, Na2S2O3 is stored in an amber glass bottle until ready for use. Primary Standard KIO3 has 2g of KI, 50mL of DI water, and 10 mL of 1.0M HCl is added then immediately titrated with Na2S2O3 until medium yellow or straw... then 5mL of starch indicator is added and titrated again until blue black color turns clear. Unknown CuO use 1.2G of Unknown, 20mL of HNO3 heated until sample dissolved, 25 mL of DI water added and boiled until clear light blue color, after cooling 1:1 NH3 added (~34.47 mL of NH4OH reagent) until permanent deep blue color amine complex, 2g of NH4HF2 added and swirled until dissolved, 3 g of KI is added then titrated immediately with Na2S2O3 until brown color of iodide is nearly gone (brown milk color), 2 g of KSCN and 3 mL of starch indicator is then added with titration continuing until disappearance of new blue black color. 4. Why is the starch indicator solution…A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to pH 3 and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of 0.527 at 283.3 nm. Five-milliliter aliquots of standard solutions containing 0.400 and 0.600 ppm of lead were treated in the same way and yielded absorbances of 0.396 and 0.599. Find the concentration of lead in the sample in ppm assuming that Beer’s law is followed.
- The label is a reagent to which he had specified on the label only the alcohol name and molecular formula of the same which was C4H10O. At the beginning of the experiment, about 50 mg reagent was diluted in deuterated chloroform with standard internal TMS and then added a specific vial (tube) for analysis of 1H and 13C spectra. When operating the equipment and ending the experiment, the teacher of discipline two being a spectrum of each 1H and one of 13C, and requests that they indicate which structure was responsible for those chemical spectra. Do you know those hired to the students who are here, qualify the structure of the referred responsible for the set of 13C and 1H spectra, as requested by the teacher. Figure 1: 1H spectrum of the unknown Figure 2: 13C spectrum of the unknown reagentState why calibrators and control for spectophotometry should be purchased in addition to the reagent?A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to pH 3 and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of 0.569 at 283.3 nm. Five-milliliter aliquots of standard solutions containing 0.400 and 0.600 ppm of lead were treated in the same way and yielded absorbances of 0.396 and 0.599. Please calculate the concentration of lead in the sample in ppm.