Q3. A.Equilibrium constant for the synthesis of ammonia at 500c', 6x 102. The reaction willshift to right in:N2+ 3H2 +2 NH3a- [NH3] -1x 10*M, [N2] .- 1x 10$M, [H2].- 2x 10 Mb- [NH:] -2x 10*M, [N2).- 1.5x 10 M,[H2] -3.54x 10'Mc- [NH:] -1x 10*M, [N2] -5 M, [H2] - 1× 10?MB. Unite of reaction equilibrium constant isbecause

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Q3. A.Equilibrium constant for the synthesis of ammonia at 500c', 6x 102. The reaction will shift to right in: N2 + 3H2 +2 NH3 a- [NH3] ,-1× 10*M, [N2].-1× 10ʻM, [H2] .- 2x 10³ M b- [NH3] -2x 10ʻM, [N2] .- 1.5x 1o*M, [H:] -3.54x 10'M c- [NH3] -1x 10*M, [N2] -5 M, [H2] - 1× 102M B. Unite of reaction equilibrium constant is because

Q3. A.Equilibrium constant for the synthesis of ammonia at 500c', 6x 102. The reaction will shift to right in: N2 + 3H2 +2 NH3 a- [NH3] ,-1× 10M, [N2].-1× 10ʻM, [H2] .- 2x 10³ M b- [NH3] -2x 10ʻM, [N2] .- 1.5x 1oM, [H:] -3.54x 10'M c- [NH3] -1x 10*M, [N2] -5 M, [H2] - 1× 102M B. Unite of reaction equilibrium constant is because

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 100CP

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