Question 20 Listen . You do some further dragon genetic research and find the following Fire breathing (Fb) and the ability to fly (FI) are 20 map units apart Fire breathing and Green eyes (G) are 3 map units apart The ability to fly and long tail (T) are 7 map units apart Green eyes and long tail are 10 map units apart recessive alleles fb cannot breath fire g blue eyes f can not fly t short tail Based on this information, the correct map order is a) Fb T G FI b) FI G T Fb c) Fb FI GT d) Fb G T FI
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Genetics Question 20
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- GENETICS Question; 1. Give the genotypes and its ratio of the dihybrid cross of FIGURE 7. Regarding this problem, you may refer the genotype of the monohybrid cross of pea flower color in Figure 6.QUESTION 5. The pedigree below follows the appearance of a rare autosomal dominant condition resulting in malformation of limbs through a family. What is the penetrance of this trait? i.e., What is the ratio between the number of individuals in the pedigree who display the trait (numerator) and the number of individuals you know from the pedigree must have the trait-determining genotype (denominator)? Enter your answer in the form of a fraction without any spaces. e.g., If your answer is “one-fourth”, enter: 1/4Question: Red color (R) allele is dominant over blue color (r) for carnations (a type of flower). You will cross a heterozygous red carnation with a blue carnation. Show all your work filling out the required parts of the diagram. Then, select the correct statement below. (Picture below) 1. 75% red - 25% blue 75% heterozygous - 25% homozygous 2. 75% red - 25% blue 75% heterozygous - 25% homozygous 3. 50% red - 50% blue 50% heterozygous - 50% homozygous 4. 25% red - 75% blue 25% heterozygous - 75% homozygous
- Question: This is a normal 3 point test cross, except that instead of regular phenotypes, you are looking at DNA markers on a gel. One parent, according to the gel, is heterozygous at each marker. The other parent is homozygous for each marker. (Again, this means it is a test cross: AaEeHh x AAEEHH --but don't be confused by that, because these are not "dominant" and "recessive" per se; the phenotype is just a band on a gel). For each offspring, figure out its genotype (homozygous or heterozygous for each gene. Then, figure that one parent made only AEH gametes, so you can cross that out if it helps.) Then treat it pretty much the same as a 3 point test cross.Question 1: In tomatoes, round fruit (O) is dominant to oblong fruit (o). Write as much as possible of the genotypes of: (A) A plant from a homozygous round-fruited stock (B) A plant from an oblong strain (C) A round-fruited plant which resulted from a testcross (D) A oblong-fruited plant which resulted from the cross of two round-fruited ones.Question In gerbils, the gene that specifies coat color is sex‑linked and has multiple alleles, as follows: B ‑ black, br ‑ brown, by ‑ yellow, and b ‑ albino. The allele br is incompletely dominant over by, the combination br by giving tan color; otherwise, dominance is in the order given ‑‑ B, br, by, b. (For your information, gerbils are mammals.) A black gerbil mated with a yellow gerbil gave one brown male and one black female offspring. What is the sex of the black parent? What is the genotype of the brown offspring? If the two offspring were to mate with each other, what is the probability that they will have a yellow offspring?
- Variations in Phenotype Expression A genetic disorder characterized by falling asleep in genetics lectures is known to be 20% penetrant. All 90 students in a genetics class are homozygous for this gene. Theoretically, how many of the 90 students will fall asleep during the next lecture?pls dont copy existing answers or i will dislike your answer thanks Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. Answer the following questions in order and show solutions whenever relevant. 1. If they have a normal child, what is the probability that he or she will be heterozygous? 2. If they have three children, what is the probability of having 2 affected children and one normal child?QUESTION 2 A male hare with the genotype AaBb is crossed with a female hare with the genotype AABb. Use a Punnet square to determine the genotypes, phenotypes and proportions in the offspring. Show all your working. [17] A = black hair a = yellow hair B = brown eyes b = blue eyes
- Question:- A female fruit fly that is heterozygous for the white-eye mutation has red-eyed sons and white-eyed sons in equal proportions: a. regardless of the genotype of the male. b. only when mated with a red-eyed male. c. only when mated with a white-eyed male. d. only when mated with a heterozygous male.Question 6: If individuals IV-4 and IV-5 mate and have a child, what is the probability that the child will have the genetic condition? Assume people mating into the pedigree do not carry the abnormal allele unless information given in the pedigree suggests otherwise. Write the probability as a fraction without any spaces, answers given as a decimal will be marked incorrect. (For example write your answer as 5/72 – note that is NOT the correct answer).Question 10. Identify the three ways that a karyotype can be organized.